Solution to Time Dilation Problem

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The discussion revolves around solving a time dilation problem involving two simultaneous events in an inertial frame K, separated by 4 km, and their measurement in a moving frame K' where the separation is 5 km. The user initially attempted to apply the length contraction and time dilation equations but struggled with the proper time. Another participant suggested using the Lorentz transformation, clarifying that the position of the origin is arbitrary and that the correct values should be used in the equations. After correcting a math error regarding the distances, the user confirmed the correct time difference as 1.0e^-5 seconds, aligning with the book's answer. The exchange highlights the importance of careful calculations and understanding of relativistic equations.
atarr3
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Hey all, I'm having a bit of trouble with this problem.

Two events occur in an inertial system K at the same time but 4 km apart. What is the time difference measured in a system K' moving between these two events when the distance separation of the events is measured to be 5 km?

I though I could use the length contraction equation to find the speed the frame is traveling and use that in the time dilation equation, but I don't know the proper time. I found the speed of frame K' to be 0.6c with respect to K.

Thanks in advance for any help you guys give.
 
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Do you know how to use the Lorentz transformation? The position of the origin is arbitrary, so you can just say one of the two events occurs at the origin (x=0 and t=0 in system K), and then in the K frame the other must be at x=4 km, t=0 since they are simultaneous. Then you can use the Lorentz transform to get x' and t' for the second event in the K' frame...
 
Yeah x' is given to us in the problem. It's 5 km. So when I use the equation t' = [t-(vx/c^2)]/0.8, I get t' = 1.25e^-5 s which would be the time difference, but the book says 1.0e^-5.
 
atarr3 said:
Yeah x' is given to us in the problem. It's 5 km. So when I use the equation t' = [t-(vx/c^2)]/0.8, I get t' = 1.25e^-5 s which would be the time difference, but the book says 1.0e^-5.
I think you just made a math error somewhere. The math in these problems is always easier if you use units where c=1, so instead of x=4 km, plug in x=(4/299792.458)=1.334e^-5 light seconds, and since t=0 this gives t' = -0.6*(1.334e^-5)/0.8 = -1.0e^-5 seconds
 
Ah yes I got it now. I had accidentally put in 5 instead of 4. Thank you so much for your help!
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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