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Consider the initial-value problem y'''+9y'=0, y(0)=3, y'(0)=-1, y''(0)=2. Given that http://forums.cramster.com/Answer-Board/Image/cramster-equation-2006318224846327831888477500005072.gif [Broken] are three linearly independent solutions of the given homogeneous linear differential equation, determine the particular solution of the initial-value problem.

So far I have y=C1(1)+C2(cos3x)+C3(sin3x) so 3=C1+C2+C3sin9 Is that right? Please help

So far I have y=C1(1)+C2(cos3x)+C3(sin3x) so 3=C1+C2+C3sin9 Is that right? Please help

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