Solve 2-D Motion: Find Direction at t=0 & t=3.5

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SUMMARY

The discussion focuses on determining the direction of a particle's motion at specific times using its trajectory equations: x = (1/2)t^3 - 2t^2 and y = (1/2)t^2 - 2t. The initial attempts to find the direction using arctan(y/x) at t=0 and t=3.5 resulted in incorrect answers of 0 degrees and 15.9 degrees. The correct approach involves differentiating the trajectory equations with respect to time to obtain the velocity components, which are necessary for accurately calculating the direction of motion.

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A particle's trajectory is defined as x = (1/2t^3 - 2t^2) m and y = (1/2t^2 - 2t)m where t is in s.

What is the particle's direction of motion, measured from the x axis, at t=0 and t= 3.5, measured in degrees counterclockwise from the x axis.

I started out by plugging in t = 0 and t = 3.5 to the equations given. I then attemped to take arctan(y/x) in both cases to find the direction of motion. my answers for these, 0 degrees and 15.9 degrees respectively, both came back as wrong.

Any clues as to what I am doing wrong/how to do it right?
 
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If you used the given equations, then you have found the LOCATION of the particle. What can you do to get information about the velocity of the particle?
 
Try differentiaing wrt t (for both x and y separately) to find the general equations for velocity.
 

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