Solve 2D Motion Homework: Throw Football 196.6m at 25°

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SUMMARY

The discussion focuses on calculating the required initial speed for a quarterback to throw a football a horizontal distance of 196.6 meters at an angle of 25 degrees. The solution indicates that the quarterback must throw the ball at a speed of 70.93 m/s. The calculations involve using the horizontal motion equation, delta x = V[SIZE="1"]0x delta t, and considering the effects of gravity on the vertical motion, specifically using the equation for maximum height.

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Homework Statement


A quarterback claims that he can throw the football a horizontal distance of 196.6 m (215 yd). Furthermore, he claims that he can do this by launching the ball at the relatively low angle of 25° above the horizontal. To evaluate his claim, determine the speed with which this quarterback must throw the ball. Assume that the ball is launched and caught at the same vertical level and that air resistance can be ignored. For comparison, a baseball pitcher who can accurately throw a fastball at 45 m/s (100 mph) would be considered exceptional.



Homework Equations


delta x = V0x delta t


The Attempt at a Solution


70.93 m/s

Tried finding the maximum height the ball would reach by using 1/2 of the length (98.3) and then plug it into the max height equation : delta y = ((initial velocity)^2 sin (theta)^2)) / 2 acceleration of gravity (-9.8 m/s^2)

This would have given me the answer for the velocity needed sine the initial and final velocity would be the same in the x-direction.
 
Last edited:
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Hi IAmSparticus! Welcome to PF! :wink:

Show us your full calculations, and then we can see what went wrong, and we'll know how to help.

Use the usual constant acceleration equations. :smile:
 

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