Solve 2D Projectile Motion Problems with Sample Equations and Steps

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SUMMARY

The discussion focuses on solving 2D projectile motion problems, specifically analyzing the trajectory of a golf ball struck at ground level. Key equations used include horizontal displacement, \(x - x_0 = (v_0 \cos \theta)t\), and vertical displacement, \(y - y_0 = (v_0 \sin \theta)t - \frac{1}{2}gt^2\). The user identifies the initial velocity as 31 m/s and the time of flight as 5 seconds, leading to the conclusion that the angle of projection, θ, is essential for calculating both horizontal distance and maximum height. The community provides guidance on how to derive θ from the given parameters.

PREREQUISITES
  • Understanding of 2D kinematics in physics
  • Familiarity with projectile motion equations
  • Basic knowledge of trigonometric functions
  • Ability to interpret graphs related to motion
NEXT STEPS
  • Learn how to derive the angle of projection, θ, from given velocity and time
  • Study the concept of maximum height in projectile motion
  • Explore the effects of varying initial velocities on projectile trajectories
  • Practice solving additional projectile motion problems using different angles and speeds
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators looking for examples to illustrate these concepts.

tmay
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Homework Statement


g'day everyone,

First of all, i would like to thank everyone on this site. You lot have helped me a lot with my homework over the last couple of weeks. anyway to the question.

A golf ball is struck at ground level. The speed of the ball as a function of the time is attached, where t = 0 at the instant the ball is struck.

A) how far does the ball travel horizontally before returning to the ground level?

B) what is the max height above the ground level attained by the ball?

Homework Equations



A)
x-x0 = (v0cos theta)t

B)
y-y0 = (v0sin theta)t - 1/2gt^2

The Attempt at a Solution



I am stuck on this question. i don't know were to start. were not given theta or the final x position or the y value. I am sure the answer to this question is in the graph and i am just not reading it properly.

from the graph i have established that the ball is in the air for 5 sec. and that the initial velocity is 31m/s. however this isn't enough information to work out the questions. any help would be greatly appreciated
 

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Welcome to PF!

tmay said:
B)
y-y0 = (v0sin theta)t - 1/2gt^2

Hi tmay! Welcome to PF! :wink:

(have a theta: θ and try using the X2 tag just above the Reply box :wink:)

You know y - y0 and v0 and t, so θ = … ? :smile:
 
thankyou tiny - tim.

i now know how to get the answer.
 

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