Solve 2sin(2x): Table of Values & Graph (-π to π)

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Homework Help Overview

The discussion revolves around preparing a table of values and plotting the graph for the function f(x) = 2sin(2x) over the domain (-π, π). Participants are exploring the implications of the function's transformations on its domain and period.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how the transformations affect the domain and period of the function. Some participants question whether the domain changes due to the horizontal compression caused by the 2x term, while others assert that the domain remains (-π, π).

Discussion Status

The discussion is active, with participants expressing differing views on the domain and period of the function. Some guidance has been offered regarding the use of a calculator to find values, but multiple interpretations of the domain are still being explored.

Contextual Notes

Participants are navigating the definitions of domain and period in the context of trigonometric functions, with some confusion regarding the effects of the function's transformations.

DethRose
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I have a question that says: prepare a table of values and plot the graph for the domain (-pie,pie) for the function f(x)=2sin(2x)

I understand how to do that for y=sinx, but for this function the wave compresses horizontally and stretches vertically so isn't the domain now (-pie/2,pie/2) and then therefore how can you make a table of values for (-pie,pie).

thanks for any help
andrew
 
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No, the domain is still (-pi,pi). Just use a calculator.
 
why is that because doesn't the 2x compress it horizontally?
 
Yes, the period will be cut in half, but you can still put x=pi, f(x)=2*sin(2*pi) in your table.
 
The period is now [itex][-\pi /2, \pi /2][/itex]. The "domain" is still all real numbers just as it is for sin(x).
 

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