Solve 7^2x+3=7^x^2: Step-by-Step Guide

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Homework Help Overview

The discussion revolves around solving the equation 7^(2x+3) / 7^(x^2) = 1, which involves exponential expressions. Participants are exploring how to manipulate the equation for clarity and solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss breaking down the term 7^(x^2) and consider alternative methods such as cross multiplying. There is also a focus on clarifying the expression in the numerator to avoid ambiguity.

Discussion Status

Some participants have provided guidance on how to express the terms clearly, while others have shared their attempts at solving the equation. There is a mix of interpretations regarding the equation's setup, and some participants have expressed confidence in their understanding.

Contextual Notes

There are questions about the correct interpretation of the numerator, with suggestions to clarify the notation used for the exponent. Participants are also repeating similar queries about breaking down the exponential term.

Mphisto
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Homework Statement


Solve the equation
7^2x+3 / 7^x^2 = 1

Homework Equations





The Attempt at a Solution



How can i "breakdown" 7^x^2? Thank you!
 
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Are you sure breaking down 7^x^2 is the only way?
Try cross multiplying it to the other side and observe.
 
AlchemistK said:
Are you sure breaking down 7^x^2 is the only way?
Try cross multiplying it to the other side and observe.

Oh I got it! I managed to solve it =) thanks!
 
Mphisto said:

Homework Statement


Solve the equation
7^2x+3 / 7^x^2 = 1
Is the numerator supposed to be 72x + 3 or 72x + 3 or 72x + 3?

I suspect that it's the first. If that's what you meant, write it as 7^(2x + 3) so that it is unambiguous.
Mphisto said:

Homework Equations





The Attempt at a Solution



How can i "breakdown" 7^x^2? Thank you!
 
Mphisto said:
Solve the equation
7^2x+3 / 7^x^2 = 1

.
.
.

How can i "breakdown" 7^x^2? Thank you!

And, to be unambiguous, type "7^(x^2)"

if you mean [itex]7^{x^2}.[/itex]
 
checkitagain said:
And, to be unambiguous, type "7^(x^2)"

if you mean [itex]7^{x^2}.[/itex]

Yeah, I meant that
 

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