Solve Amplitude for Guitar String Vibrating in Fundamental Mode

[weathercheck]

Homework Statement

A guitar string is vibrating in its fundamental mode, with nodes at each end. The length of the segment of the string that is free to vibrate is 0.381 m. The maximum transverse acceleration of a point at the middle of the segment is 8600 m/s^2 and the maximum transverse velocity is 3.50 m/s.

The Attempt at a Solution

Now i thought i has calculated it correctly i got A= 10.35m

I used the fundamental F = v/2l threw that into a= Aw^2

This question is making me angry! can anyone help me out! ? cheers! ;)

 

[kbaumen]

What is the question?

 

[weathercheck]

What is the amplitude of the standing wave?

 

[Ginerva123]

Are you familiar with the equation of a standing wave? If you are, then you can differentiate it once and equate it to your maximum velocity, and then equate your maximum acceleration to the second derivative of the standing wave equation. You can then find A and w.

 

[weathercheck]

how do i go about differentiating the wave equation?

thanks

 

[Ginerva123]

Differentiate with respect to t, using the chain rule.

 

[weathercheck]

can somebody please please, differentiate this for me as an example

(A.Sin(kx)).(sin(wt))

with respect to t, I'm losing my nut here! Feel so dumb

thanks a bunch

 

[Vidatu]

You can't find derivatives on your own?