Solve Amplitude for Guitar String Vibrating in Fundamental Mode

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SUMMARY

The discussion centers on calculating the amplitude of a guitar string vibrating in its fundamental mode, specifically a string length of 0.381 m with a maximum transverse acceleration of 8600 m/s² and a maximum transverse velocity of 3.50 m/s. The user initially calculated the amplitude as 10.35 m using the formula F = v/2l and the relationship a = Aw². To find the correct amplitude, participants suggest differentiating the standing wave equation A·sin(kx)·sin(wt) with respect to time and equating the results to the maximum velocity and acceleration. This approach provides a systematic method to derive the amplitude and angular frequency.

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Homework Statement


A guitar string is vibrating in its fundamental mode, with nodes at each end. The length of the segment of the string that is free to vibrate is 0.381 m. The maximum transverse acceleration of a point at the middle of the segment is 8600 m/s^2 and the maximum transverse velocity is 3.50 m/s.


The Attempt at a Solution



Now i thought i has calculated it correctly i got A= 10.35m

I used the fundamental F = v/2l threw that into a= Aw^2

This question is making me angry! can anyone help me out! ? cheers! ;)
 
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What is the question?
 
What is the amplitude of the standing wave?
 
Are you familiar with the equation of a standing wave? If you are, then you can differentiate it once and equate it to your maximum velocity, and then equate your maximum acceleration to the second derivative of the standing wave equation. You can then find A and w.
 
how do i go about differentiating the wave equation?

thanks
 
Differentiate with respect to t, using the chain rule.
 
can somebody please please, differentiate this for me as an example

(A.Sin(kx)).(sin(wt))

with respect to t, I'm losing my nut here! Feel so dumb

thanks a bunch
 
You can't find derivatives on your own?
 

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