Solve an equation with complex numbers

Click For Summary
SUMMARY

The discussion focuses on solving the quadratic equation 3.1(ω)^2 - 6.2iω - 20 = 0, where the presence of the imaginary unit 'i' in the linear term can be intimidating for some students. Participants confirm that the equation can be approached using standard quadratic methods, treating 'i' as a constant. The quadratic formula is applicable, and the correct formulation for ω is ω = (6.2i ± √((6.2i)² + 80)) / 2, emphasizing the importance of handling complex arithmetic correctly.

PREREQUISITES
  • Understanding of quadratic equations
  • Familiarity with complex numbers and the imaginary unit 'i'
  • Knowledge of the quadratic formula
  • Basic skills in complex arithmetic
NEXT STEPS
  • Study the quadratic formula in-depth
  • Learn about complex number arithmetic and its applications
  • Explore examples of solving quadratic equations with complex coefficients
  • Investigate the implications of complex solutions in control systems
USEFUL FOR

Students studying control systems, mathematics enthusiasts, and anyone looking to enhance their understanding of complex numbers in quadratic equations.

2slowtogofast
Messages
134
Reaction score
1

Homework Statement


I am doing a problem where I have to design a controller for a system. I have to solve the below equation for ω

3.1 (ω)^2 - 6.2iω - 20

Homework Equations





The Attempt at a Solution



I am not sure how to start It looks like a quadratic but I don't know what to do with the i
 
Physics news on Phys.org
Looks like a quadratic, quacks like a quadratic. It is probably quadratic. You can use all the normal methods to solve it. The i is just part of the coefficient of the linear term.
 
I can't really see an equation anywhere. All I see is an expression in \omega. An equation must contain an "=".
 
Yes, that's a quadratic. What it isn't is an equation! What is the problem really? Do you know the quadratic formula?
 
Sorry, I thought he meant to factor it. Good point!
 
Ok, it's the "i" that's causing the problem for him. That's intimidating to a lot of students not familiar with complex variables.

The think to do 2slow is not be intimidated by them. Treat them just like constants but remember the complex arithmetic i times i is minus one. So you have:

w^2-6.2iw-20=0

(I heard a quack)

alright, that 6.2i is just a constant. Treat it just like if you were solving:

w^2-aw-20=0

as long as you remember to do the complex arithmetic with i's so:

w=\frac{6.2i\pm\sqrt{(6.2i)^2+80}}{2}

Not gonna' have problems with that (6.2i)^2 thing right?
 

Similar threads

  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K