Solve Battery & Capacitors Network: Find C2,C3 PD & Q3 Charge

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SUMMARY

The discussion focuses on solving a circuit problem involving a battery and capacitors, specifically determining the potential differences across capacitors C2 and C3, as well as the charge on capacitor C3 (Q3). Given values include Q1 at 7.9e-6 C, C1 at 7.1e-6 F, C2 at 1.9e-6 F, and energy stored in C2 at 5.6e-6 J. The potential difference across C1 is calculated to be 1.126 V, and it is established that C2 and C3 are in parallel, leading to the conclusion that their potential differences are equal.

PREREQUISITES
  • Understanding of capacitor circuits and their configurations (series and parallel)
  • Knowledge of the energy stored in capacitors formula: W=1/2 * CV^2
  • Familiarity with charge relationships in capacitors
  • Basic circuit analysis techniques
NEXT STEPS
  • Calculate the potential difference across C2 using the formula W=1/2 * CV^2
  • Determine the charge on capacitor C2 using Q2=C2V2
  • Find the charge on capacitor C3 (Q3) using the relationship Q3=Q1-Q2
  • Explore the implications of series and parallel capacitor configurations on total charge and voltage
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing capacitor networks and energy storage in electrical circuits.

ahazen
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I have a circuit consisting of a battery and several capacitors, some quantities are known and some are not. The capacitors were completely uncharged before the battery was attached and we are considering the static situation. (Be sure to keep at least 3 sig. figs. in your answer for all parts of this problem.)

Given:
Q1: 7.9e-6
C1: 7.1e-6
C2: 1.9e-6
Energy stored on C2: W=5.6e-6 J
C2 is parallel to C3

I found:
the potiential distance across C1 is 1.126 V

I need to find:
-Potenital distance across C2
-Potential difference across C3
-The charge of Q3 on C3


Can you please help me? Thank you:)
 
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1) You know the relation
W=1/2 * CV^2
You can find V2 because you know C2 and W2

2) Since C2 and C3 are parallel V2=V3 (Pot. diff. across C2 and C3 are same)3) I assumed C1 is in series with C2 || C3. Q1 is known. Since they are in series total charge in C2||C3 is Q1. (In series connected capacitors the amount of charge stored in each capacitor is same). You can find charge in C2 using relation
Q2=C2V2.
From this Q3= Total charge in C2||C3 (ie., Q1) - Q2
 
Ok, thank you:)
 

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