Solve Challenging Physics Question: Block + Bullet UP Motion

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Homework Help Overview

The problem involves a block of wood suspended by a thread and a bullet fired vertically upwards into the block. The scenario raises questions about the speed of the block and bullet after the collision, the total kinetic energy immediately after, and the maximum height reached thereafter.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for the original poster to show their work before receiving help. Some express skepticism about the poster's approach and attitude towards the guidelines.

Discussion Status

The discussion is ongoing, with participants emphasizing the importance of demonstrating prior efforts. There is a mix of light-hearted banter and serious reminders about forum etiquette, indicating a lack of consensus on how to proceed with the problem.

Contextual Notes

Participants note the forum's guidelines that require users to show their work before asking for assistance. There is an underlying tension regarding the original poster's request for solutions without prior attempts.

Willtd
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This question is one i got from uni. i just can't seem to get the right answers. Please post your worked solutions, i will tell you if you get the answer found on my sheet. Best of luck Guys, you might need it.

A 3.00 kg block of wood is suspended at rest by a thin thread attached to a supporting beam. A bullet of mass 32.0 g is fired vertica1ly upwards with velocity 415 m/s into the wood directly above it. The block and the bullet inside it move upwards together.


1 Determine the speed of the upward moving block and bullet immediately after the collision.
.
2 Calculate the total kinetic energy of the block and bullet immediately after the collision.

3 Calculate the maximum height the block and bullet reach.
 
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Sounds like a straightforward homework problem to me! :wink:

Why don't you show what you've done so far?
 
Welcome to the Forums Willtd,

According to our forum guidelines, one is expected to show one's own efforts before asking for help. So if you post your attempted solution, we might be able to show you where've you've gone wrong.

In addition, we have dedicated Homework & Coursework forums for such questions.

Edit: The Doc Strikes again.
 
Do you think you are some kind of a professor? hehe

Please obey the guidelines of these forums.
 
My Attempt

I got it! Here is a solution for anybody who wants it. :)

1. m1v1 = m2v2
.032x415 = 3.032v
v = 4.379

2. Total Ke = 0.5 x m x v^2
= 0.5x 3.032x4.38^2
= 29.1
3. v^2 = u^2 +2as
v (final speed) = 0
s = sqrt [(4.38^2) / (2x9.8)]
= 0.98m
 
hehe.. are you joking with us? :)
 
Yeh man ur cool

malawi_glenn said:
hehe.. are you joking with us? :)

Maybe you should help next time m8 :D
 
Willtd said:
Maybe you should help next time m8 :D

1. you did not show us your work so far

2. You wished us good luck, and said that we would need it.

That is not an attitude that I and others don't like. There is a guideline here that states that you shall show us work done so far, so we can HELP, not just solve the problem for you. That is probably why no one helped you this time, and you will meet much much more difficult problems than this one in the future...
 

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