Solve Circle Equation: Complete the Square for Center & Radius

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    Trigonometry
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Homework Help Overview

The discussion revolves around completing the square to find the center and radius of a circle from a given equation. The original equation provided is y² + 12y = 17 - x² + 2x, which participants are attempting to manipulate into the standard form of a circle's equation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are discussing how to rearrange the equation and group terms appropriately. There are questions about the process of completing the square and whether certain terms would cancel out in the manipulation.

Discussion Status

Some participants are sharing their attempts at completing the square, while others are questioning the correctness of these attempts. There is a suggestion to refer to a textbook or online resource for clarification, indicating that guidance has been offered without reaching a consensus.

Contextual Notes

Participants express uncertainty about the steps involved in completing the square and the implications of their manipulations. There is a mention of needing to move terms around and the challenge of correctly applying the method.

srv96
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Homework Statement



I have no idea how to figure this out. Please help!:)
Complete the square to find the center and radius of the circle:
(equation of a circle:(x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center and r is the radius)

y^2+12y=17-x^2+2x

(^2 = squared)
 
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srv96 said:

Homework Statement



I have no idea how to figure this out. Please help!:)
Complete the square to find the center and radius of the circle:
(equation of a circle:(x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center and r is the radius)

y^2+12y=17-x^2+2x
Move all of the terms except 17 to the left side, grouping the terms in x together and the terms in y together.

Do you know how to complete the square?
 


After completeing the square, I ended up with
y(y+12)+x(x-2)=17
Would the extra y's and x's cancel out and would the answer just become
(x-2)^2 + y(y+12)^2=square root of 17
and thanks for the previous help:)
 


srv96 said:
After completeing the square, I ended up with
y(y+12)+x(x-2)=17
Would the extra y's and x's cancel out and would the answer just become
(x-2)^2 + y(y+12)^2=square root of 17
and thanks for the previous help:)
No, that's not completing the square. Check your textbook again (if you have one). Or, here's an online lesson:
http://www.purplemath.com/modules/sqrcircle.htm"
 
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