Solve Conservation of Momentum Problems | Physics Homework Help

  • Thread starter Thread starter Dr physics
  • Start date Start date
  • Tags Tags
    Physics
Click For Summary

Homework Help Overview

The discussion revolves around the principle of conservation of momentum, specifically applied to two problems involving a man on ice and a collision between two balls. The first problem involves a man throwing a book to move across a frozen pond, while the second concerns an elastic collision between two balls of different masses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum, questioning the setup and definitions involved in the problems. There are attempts to derive equations and solve for unknowns, with some participants expressing confusion over algebraic manipulations and the correct interpretation of variables.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to approach the problems. There is a mix of attempts to clarify concepts and correct misunderstandings, particularly regarding the application of formulas and the interpretation of momentum in the context of the problems.

Contextual Notes

Some participants note the importance of showing work according to forum rules, while others highlight the need for clarity in units and the distinction between mass and weight. There is also mention of the challenges faced by beginners in physics.

  • #31
OK, now try to do the same thing with your previous equation. It really is no different.

m_1V_1+m_2V_2=0

Can you show the following two steps?

1.) Subtract m_2V_2 from both sides.
2.) Divide by m_1.

Then you will have solved for V_1. But be careful about the negative sign that appears after step 1.
 
Physics news on Phys.org
  • #32
M1 + m2V2 = 0
M1 + M2V2 - M2V2 = 0 -M2V2
M1 / M1 = M2V2 / M1
 
Last edited:
  • #33
Dr physics said:
M1 + m2V2 = 0

That is not the equation. Where did V1 go??
 
  • #34
o sry,

M1V1 + m2V2 = 0
M1V1 + M2V2 - M2V2 = 0 -M2V2
M1V1 / M1V1 = M2V2 / M1V1
 
  • #35
Dr physics said:
o sry,

M1V1 + m2V2 = 0

OK, that's the equation.

M1V1 + M2V2 - M2V2 = 0 -M2V2

Yes.

M1V1 / M1V1 = M2V2 / M1V1

No. First of all, what happened to that negative sign that I cautioned you to be careful about? You do understand that 0-M2V2=-M2V2, right? And second, why are you dividing by M1V1? You're supposed to be solving for V1. That's why I said in step 2, "divide by m_1"!
 
  • #36
im sorry i knew i shouldn't have, made a silly mistake sry about that.

M1V1 + m2V2 = 0
M1V1 + M2V2 - M2V2 = 0 -M2V2 = -M2V2
M1V1 / M1V1 = -M2V2 / M1
 
  • #37
Dr physics said:
im sorry i knew i shouldn't have, made a silly mistake sry about that.

M1V1 + m2V2 = 0
M1V1 + M2V2 - M2V2 = 0 -M2V2 = -M2V2

Right.

M1V1 / M1V1 = -M2V2 / M1

Again, you're dividing by M1V1. This is not right. The last line should read:

M1V1/M1=-M2V2/M1

Then we obtain V1=-M2V2/M1. You can then plug in the numbers you were given to find V1.
 
  • #38
M2 = 1.2kg
V2 = 5m/s
M1 = 750 N
V1 = ?

V1 = -M2V2/M1
V1 = -1.2 * -5 / 76.53 = 0.0784

is that correct?
 
  • #39
Dr physics said:
M2 = 1.2kg
V2 = 5m/s
M1 = 750 N

As I have already explained to you, M1 is not 750N. It is 76.53 kg. But you did use the correct number below, so this mistake is minor.

V1 = ?

V1 = -M2V2/M1
V1 = -1.2 * -5 / 76.53 = 0.0784

is that correct?

No, it isn't. The answer should obviously be negative. Think about what you're doing. If the book moves in one direction, then obviously the man has to move in the other direction! Why did you insert that extra negative sign in your last step? It shouldn't be there.
 
  • #40
V1 = ?

V1 = -m2v2/m1
V1 = -1.2 * 5 / 76.53
V1 = -6 / 76.53 = -0.0784
 
  • #41
Dr physics said:
heres a list of question I am having difficulty with.

1)define clearly the principle of conservation of momentum and apply this to solve the following problem:
A man weighing 730N stands in the middle of a frozen pound of a radius 5.9m. he is unable to get to the other side because of lack of friction between his shoes and the ice. to overcome this problem, he throws his 1.2kg book horizontally towards the north shore at a speed of 5m/s. how long does it take him to reach the south shore?

to work out how long it take him to reach the south shore do you use this formula

d = vi + vf / 2 * t = t = vi + vf / 2 / d

t = -0.0784 + 5 / 2 / 5.9
= 4.922 / 2 / 5.9
= 5.9 / 2.461
t = 2.34 s

hope that's right
 
Last edited:
  • #42
Dr physics said:
V1 = ?

V1 = -m2v2/m1
V1 = -1.2 * 5 / 76.53
V1 = -6 / 76.53 = -0.0784

Correct. And the units are m/s.
 
  • #43
Dr physics said:
to work out how long it take him to reach the south shore do you use this formula

d = vi + vf / 2 * t = t = vi + vf / 2 / d

No, you don't use that formula. In that formula, vi and vf refer to the initial and final velocities of the same object under uniform acceleration. You are trying to apply it to two different objects. You need to stop guessing and start thinking if you are going to succeed at this.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
7
Views
3K