Solving Squid Propulsion with Momentum Conservation Equation

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SUMMARY

The discussion focuses on solving a physics problem involving squid propulsion using the momentum conservation equation. The key equation applied is p=mv, where the initial momentum of the squid (1.2 kg moving at 0.6 m/s) is set equal to the final momentum after expelling water. The final calculation reveals that the velocity of the expelled water is 22.5 m/s, derived from the equation -2.25 kg·m/s / -0.10 kg. This demonstrates the principle of momentum conservation in a real-world scenario.

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Homework Statement


squidward.PNG


Homework Equations


p=mv
j=Δp[/B]

The Attempt at a Solution


I am confused as to how to approach this problem. so it looks like squidwards mass is changing from 1.2kg to 1.1kg after he shoots out the water from his butt. I know that momentum is conserved so

1.1*2.7 - 1.2*0.6 should = 0.
this leaves -2.25kgm/s left. so then i would have to divide by his mass? so his mass is currently 1.1kg which gives a speed of 2.0454545m/s
 

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ok i am completely wrong here and don't know what i am doing
 
Ahh ok i got it.
So the momentum is conserved

1.2kg*.60m/s = 1.1kg*2.7m/s - .10kg*vwater

-2.25kgm/s / -.10kg = vwater = 22.5m/s
Why is that so small ? i tried to edit it


-2.25kgm/s / -.10kg = vwater = 22.5m/s​
 

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