Solve Delta Potential Well for Scattering Matrix & Prove Unitarity

Click For Summary
SUMMARY

The discussion focuses on solving the scattering matrix for a delta potential well defined by the equation 2m/hbar² V(x) = λ/a δ(x-b). The scattering matrix is expressed as S = [[2ika/(2ika-λ), (e^(-2kib) λ)/(2ika-λ)], [(e^(2kib) λ)/(2ika-λ), 2ika/(2ika-λ)]]. The participants confirm that the matrix is unitary and establish that bound states occur when λ < 0. Key boundary conditions and wave functions are discussed to derive the reflection (R) and transmission (T) coefficients.

PREREQUISITES
  • Understanding of quantum mechanics, specifically scattering theory.
  • Familiarity with delta function potentials and their implications in quantum systems.
  • Knowledge of boundary conditions and wave function continuity in quantum mechanics.
  • Proficiency in using complex exponentials in wave functions.
NEXT STEPS
  • Study the derivation of the reflection and transmission coefficients for delta potentials.
  • Learn about the implications of unitarity in scattering matrices.
  • Explore the conditions for bound states in quantum mechanics, particularly for potentials with λ < 0.
  • Investigate the use of \LaTeX for presenting mathematical equations in discussions.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying scattering theory and delta function potentials, will benefit from this discussion.

Felicity
Messages
25
Reaction score
0

Homework Statement



consider the scattering matrix for the potential

2m/hbar2 V(x) = λ/a δ(x-b)

show that it has the form

(2ika/(2ika-λ) , (e-2kib) λ/(2ika-λ)
(e2kib) λ/(2ika-λ) , 2ika/(2ika-λ)

(I've used commas just to separate terms in the matrix)

prove that it is unitary and that it will yield the condition for bound states when the elements of that matrix becoe infinite (this will only occur for λ < 0)

Homework Equations



suppose the matrix is expressed as

S11 S12
S21 S22

where S11 = (2ika/(2ika-λ)
S12 = (e-2kib) λ/(2ika-λ)
S21 = (e2kib) λ/(2ika-λ)
S22 = 2ika/(2ika-λ)

The Attempt at a Solution



I see that this is a delta potential well at x=b

ok so I know that S11 = T S21= R S22 = T and S12 = R where T and R are the reflection and transmission coefficients so I figure that if I can find those then I show the s-matrix in the above form so here it goes...

take

u(x) = Arekx +Bre-kx x < b

= Ale-kx +Blekx x > b

the boundary condition is (du/dx at x = b+) - (du/dx at x = b-) = λ/a u(b)

so

k(Arekb -Bre-kb+Ale-kb -Blekb)= λ/a u(b)

then for an incoming particle that can be either reflected or transmitted I make Ar= 1 Al = r Bl=0 and Br=t
where r2 = R (reflection coefficient and t2= t (transmission coefficient)

to get

ekb-te-kb + re-kb= λ/a u(b)

so how do I solve for r and t separately and how do I get rid of the u(b)?

Thank you

Felicity
 
Physics news on Phys.org
Aren't you missing a bunch of "i"s in your wave-function exponents?

What is the potential for x \neq b? What are the wave-functions in such a region of space?

PS: These forums support \LaTeX. See this thread: https://www.physicsforums.com/showthread.php?t=8997 or click on my tex to see the code.
 
Thank you for replying to my question,

About the i's

I realize now that I was assuming that λ was negative which is the condition for bound states but I realize that this was not a good assumption (turns out this only a well when λ <0) and that the i's should in fact be there.

About the potential

I believe the potential where x does not equal b is 0 however in class my professor indicated that the particle/wave in such a potential does not actually live at b but around it and yet it is still bound (assuming a well)

Even with the i's however, I still end up with one equation featuring r, t and u(b). I'm not sure how to get the scattering amplitudes from this or if I am even on the right track.

Thanks for the heads up about Latex, I will familiarize myself with the system

Thanks again,

Felicity
 
So combining all of that and starting over... you should have, for an incoming particle from the left:

u_l(x&lt;b)=e^{ikx}+re^{-ikx}~~~~~~~~~~~~~~~~~~~~~(1)

u_r(x&gt;b)=te^{ikx}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

and

\left[\frac{du_l}{dx}\right]_{x=b-}-~\left[\frac{du_r}{dx}\right]_{x=b+}=\frac{2m\lambda}{\hbar ^2} \int_{b-}^{b+} \delta (x-b)u(x)dx~~~(3)

with (3) evaluated in the limit at b- \rightarrow b from the left and b+ \rightarrow b from the right.

Also keep in mind that while there is a discontinuity in du/dx, there is none in u(x) itself.

u_l(x=b)=u_r(x=b)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(4)

This is the second boundary condition that you need to solve for the coefficients.
 

Similar threads

Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
Replies
1
Views
2K