Solve Diff Eqns for Polar Functions & Critical Points

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The discussion focuses on solving differential equations for polar functions and locating critical points in two-dimensional systems. The user seeks guidance on converting Cartesian equations into polar coordinates and expresses confusion about the process, particularly regarding the derivatives. For the first question, it's suggested to rewrite the equations using polar coordinates and apply the product rule for derivatives. In addressing the second question, critical points are identified where the derivatives x' and y' equal zero. Overall, the user is looking for foundational support to tackle these mathematical concepts effectively.
vinverth
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Hello everyone..Find it embarrassing enough on asking a question on my very first post but I've been an avid reader of the forums for the past couple of months and been finding what i need for all my assignments here.So a big Thank You to all who've helped.I'm A EE grad and have a math course in my final semester so am a complete noob when it comes to grad math courses,a little consideration here while posting replies or even answers.So here i have a couple of q's whose answers or at least a decent start I've been searching all over the web.

1.Find the differential equations for the polar functions r,ө of the following two-dimensional systems.

(a) x'=x+y
y'=x-y

2.Locate the critical points of the following systems.

(a) x'=x-y²
y'=x²-y²
These are both separate questions.Answers to anyone pleasezzz..
(b) x'=sin(y)
y'=cos(x)Thank You again to everyone and please bail me out guys!
 
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vinverth said:
1.Find the differential equations for the polar functions r,ө of the following two-dimensional systems.

(a) x'=x+y
y'=x-y

Polar coordinates are defined by

x = r \cos\theta,~y=r\sin\theta.

You should rewrite the equations using these and solve for r', \theta'.

2.Locate the critical points of the following systems.

(a) x'=x-y²
y'=x²-y²
These are both separate questions.Answers to anyone pleasezzz..
(b) x'=sin(y)
y'=cos(x)

Critical points are the points where the derivatives of functions either don't exist or are zero.
 
I already tried that approach but it got me nowhere..what confuses me is the fact that the equations are already in their first derived form for both q's wrt x and y.
i tried to plug in x=rcosө and y=rsinө which gives me x'=rcosө+rsinө.
(rcosө)'=rcosө+rsinө
How do i proceed frm here..

and for the second q..since x'=sin(y) and y'=cos(x)..do i just check for what values x' and y' are 0 and figure out their critical points.
Any kind of help or a start is appreciated..and I've been trying to solve them in every possible way via research on internet.but maybe its just my fundamentals..too weak at them..like i said before i hail from a diff background
 
vinverth said:
I already tried that approach but it got me nowhere..what confuses me is the fact that the equations are already in their first derived form for both q's wrt x and y.
i tried to plug in x=rcosө and y=rsinө which gives me x'=rcosө+rsinө.
(rcosө)'=rcosө+rsinө
How do i proceed frm here..

Use the product rule for derivatives

(fg)' = f' g + f g'.

and for the second q..since x'=sin(y) and y'=cos(x)..do i just check for what values x' and y' are 0 and figure out their critical points.

The (x,y) values for which either x'=0 or y'=0 are critical points.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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