Solve Differential Equations with Ease - No More Struggles!

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Homework Help Overview

The discussion revolves around solving a differential equation, with participants analyzing the manipulation of trigonometric functions within the equation.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are examining the correct application of trigonometric identities and the proper multiplication of terms in the equation. There is an exploration of how to simplify the expression involving tan(x) and its relation to sin(x) and cos(x).

Discussion Status

Some participants have provided clarifications regarding the algebraic manipulation of the equation, noting specific errors in the original setup. There seems to be a productive exchange of ideas, with acknowledgment of mistakes and corrections being made.

Contextual Notes

There is a focus on ensuring that all terms are correctly accounted for in the equation, with specific attention to the roles of trigonometric functions. The discussion reflects a collaborative effort to clarify misunderstandings without reaching a definitive solution.

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Differential Equations PLEASE!

**problem solved**
 
Last edited:
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It seems that you didn't multiply tan(x) with the -cos(x) term.
 


nicksauce said:
It seems that you didn't multiply tan(x) with the -cos(x) term.

i turned tan(x) into sinx/cosx and canceled out the cosx, and was left with

-sin^2 x + cos^2 x + sinx + sin^2 x -cosx = cos^2 x

any ideas?
 


Like I said, you wrote:

-sin^2 x + cos^2 x +sinx +[tan x] sinxcosx -cosx = cos^2x

When it should be:

-sin^2 x + cos^2 x +sinx +[tan x]( sinxcosx -cosx) = cos^2x
 


nicksauce said:
Like I said, you wrote:

-sin^2 x + cos^2 x +sinx +[tan x] sinxcosx -cosx = cos^2x

When it should be:

-sin^2 x + cos^2 x +sinx +[tan x]( sinxcosx -cosx) = cos^2x

aww, such a simple mistake, thanks a lot :)
 

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