Solve Eigenvalue Problem: q, x, A, Ak

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SUMMARY

The discussion centers on proving that if q is an eigenvalue of a square matrix A with corresponding eigenvector x, then q^k is an eigenvalue of A^k, with x remaining the corresponding eigenvector. The proof begins with the equation 0=(A-qI)x, which needs to be manipulated to demonstrate that (A^k-q^kI)x=0. Participants suggest using an alternative definition of eigenvalues to simplify the proof process, emphasizing the minimal algebra required for resolution.

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Homework Statement


Given that q is an eigenvalue of a square matrix A with corresponding eigenvector x, show that qk is an eigenvalue of Ak and x is a corresponding eigenvector.

Homework Equations


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The Attempt at a Solution


I really haven't been able to get far, but;

If x is an eigenvector of A corresponding to q, then;
0=(A-qI)x
To complete the proof I need to use this equation to show that (Ak-qkI)x=0, and this is where I'm having trouble.
If anyone has time to help I would really appreciate it.
 
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I think you might want to use a different definition of an eigenvalue. Then the proof is really easy, with like hardly any algebra at all.
(edit: well, rearrange the one you have, I guess)
 

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