Solve Elastic Collision: Momentum vs Kinetic Energy

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BradP
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Homework Statement



Two hard spheres collide elastically. Sphere 1 has a mass of 2 kg and an initial velocity of 3 m/s. Sphere 2 has a mass of 4 kg and is initially at rest. Sphere 1 collides head on with sphere 2 and comes to an immediate stop. Solve for the velocity of mass 2 using (a) conservation of momentum and (b) conservation of kinetic energy.



Homework Equations



Momentum = constant
m1*v1 = m2*v2

Kinetic energy = constant
m1*(v1^2) = m2*(v2)^2



The Attempt at a Solution



Using conservation of momentum,

2*3 = 4*v
v = 1.5 m/s.

Using conservation of kinetic energy,

.5*2*3^2=.5*4*v^2
v = 2.12 m/s.

My question is why the velocities are different. If this collision is elastic, shouldn't using kinetic energy and conservation of momentum give the same answer?
 
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Hi BradP! :smile:

(try using the X2 and X2 icons just above the Reply box :wink:)
BradP said:
Two hard spheres collide elastically. Sphere 1 has a mass of 2 kg and an initial velocity of 3 m/s. Sphere 2 has a mass of 4 kg and is initially at rest. Sphere 1 collides head on with sphere 2 and comes to an immediate stop. Solve for the velocity of mass 2 using (a) conservation of momentum and (b) conservation of kinetic energy.

My question is why the velocities are different. If this collision is elastic, shouldn't using kinetic energy and conservation of momentum give the same answer?

Yes, it's a ridiculous question.

"Elastically" means with conservation of energy, but on the given figures, energy and momentum can't both be conserved.

The teacher is obviously trying to illustrate something for you … but I've no idea what! :redface:
 
Oh, I see. Is it because that sphere 2 is heavier, sphere 1 would not actually stop when it hit it? It would collide and roll backwards at a slower velocity, right?
 
It would if they were the same mass, like a cue ball. But the heavier the second sphere is, the more it approaches something like a ball hitting a wall. So in this problem, it would roll backwards. Thanks :)