Solve Equation for x & y: 1+z=3-2i

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Homework Help Overview

The problem involves solving for the variables x and y in the equation 1 + z = 3 - 2i, where z is defined as x + iy. Participants are exploring how to separate the equation into real and imaginary components to find the values of x and y.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • One participant attempted to substitute z with x + iy and noted that their result was x = y. Another suggested separating the equation into real and imaginary parts to find equalities. There is a question about whether the equation simplifies directly to x + iy = 2 - 2i.

Discussion Status

The discussion is active, with participants exploring different interpretations of the equation. Some guidance has been offered regarding the separation of real and imaginary parts, but there is no explicit consensus on the final values of x and y yet.

Contextual Notes

Participants are working within the constraints of the problem as presented, with some confusion regarding the implications of their manipulations and the relationships between the variables.

Ry122
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Given z = x + iy
find x and y if
1 + z = 3 - 2i
I tried subbing x+iy into z and solving but all i got was x = y.
The answer in the back is x=2 y=-2
 
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Separate 1+(x+iy)=3-2i into real and imaginary parts. They have to be equal separately.
 
so is it just x+iy=2-2i ?
 
Ry122 said:
so is it just x+iy=2-2i ?

yeah and from here x=2, y=-2, because like Dick said the real part and the imaginary part on both sides has to be equal. Like
[tex]a+bi=c+di<=>a=c, \ \ and \ \ b=d[/tex]
 

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