Solve f'(c)*(b-a): Net Change at c

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SUMMARY

The expression f'(c)*(b-a) represents the net change in the function f over the interval [a, b], where f'(c) is the derivative of f at the point c. This formula derives from the Mean Value Theorem, which states that there exists at least one point c in the interval (a, b) where the instantaneous rate of change (the derivative) equals the average rate of change over that interval. Therefore, f'(c)*(b-a) quantifies the total change in the function's value from a to b, not just at the point c.

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Kibbel
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Homework Statement


This is my own question. I am trying to understand what

f'(c)*(b-a) exactly means. I know its (deltaY/deltaX)*deltaX, which gives us deltaY, but does that mean its the net change in Y over the entire interval, or just at point c?
 
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This doesn't inherently mean anything about y or x.

f'(c) is the derivative of f at c; that is:

[tex]\lim_{h\rightarrow 0} \frac{f(c+h)-f(c)}{h}[/tex]

f'(c) is the slope of a tangent to the graph of f at c.

Now b and a don't inherently mean anything either; they're probably endpoints of some interval. It looks like you're encountering this in the context of the mean value theorem or something like that. Maybe if you gave some more context, we could clarify this.
 

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