Solve for Smallest Theta for Slider to Reach A

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SUMMARY

The discussion focuses on solving for the smallest angle theta required for a slider to pass through point D and reach point A in a vertical hoop system. The parameters include a spring constant of k = 40 N/m, a slider mass of 200 g, and a radius of r = 0.3 m. The energy conservation equations utilized are based on gravitational potential energy and spring potential energy. The user encountered difficulties in rearranging the equations to isolate theta, specifically in the equation mgcos(theta) + 0.0018277*theta^2 = 1.962.

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Homework Statement


k = 40 N/m
mass of slider = 200 g
EDIT r = 0.3 m
Hoop is VERTICAL, undeformed length of the spring is when spring is in position AB, slider NOT attached to spring.

Find smallest value for theta such that the slider will pass through D and reach A (see picture).

Homework Equations



s = r*theta
1/2 k * x^2
mgh
1/2 mv^2

The Attempt at a Solution



I set up the initial and final energy equations but couldn't figure out how to solve them. =P

Denoting @ as theta:

mgr(1-cos(@)) + 1/2*k(r@)^2 = mg*2r

After plugging in numbers and rearranging, I found:

mgcos(@) + 0.0018277@^2 = 1.962

I don't know how to solve for @ in that equation. Also, in the spring term of 1/2kx^2, I replaced x by r@ (s = r@) and multiplied @ by pi/180 to convert to radians for that term.
 

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Until you post a clearar diagram, I doubt anyone will be able to entirely check your equations.
 
That's the diagram in my book really...It's a vertical circle with a slider and a spring attached to point A (slider NOT attached to spring)

And my equation is wrong I discovered, but have NO clue what the right one is.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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