k = 40 N/m
mass of slider = 200 g
EDIT r = 0.3 m
Hoop is VERTICAL, undeformed length of the spring is when spring is in position AB, slider NOT attached to spring.
Find smallest value for theta such that the slider will pass through D and reach A (see picture).
s = r*theta
1/2 k * x^2
The Attempt at a Solution
I set up the initial and final energy equations but couldn't figure out how to solve them. =P
Denoting @ as theta:
mgr(1-cos(@)) + 1/2*k(r@)^2 = mg*2r
After plugging in numbers and rearranging, I found:
mgcos(@) + 0.0018277@^2 = 1.962
I don't know how to solve for @ in that equation. Also, in the spring term of 1/2kx^2, I replaced x by r@ (s = r@) and multiplied @ by pi/180 to convert to radians for that term.