MHB Solve for the angles in a triangle

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The discussion revolves around solving for the angles in an isosceles triangle. The user initially calculated x as 30 and y as 60, assuming the triangle's base angles were equal. After further calculations, they revised their values to x = 40 and y = 80, which was confirmed as correct by another participant. The equation used was 60 + x + 2x = 180, leading to the correct angle measures. The conversation highlights the importance of verifying calculations in geometry.
gazparkin
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Hi,

Could someone check that I'm right with this one, or put me right! I've worked the value out as

x=30 and y (2x) = 60. I've come to this as I think it's an isosceles triangle so the base angles would be equal. Am I right?

Thank you!

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60 + x + y = 180

if y = 2x ...

60 + x + 2x = 180

try again ...
 
Is it x = 40 and y =80??
 
gazparkin said:
Is it x = 40 and y =80??

Yes, that's correct.
 
catmitt98 said:
Yes, that's correct.

Thank you for your help.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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