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Solve for the tension in T1 and T2

  • Thread starter lilgen
  • Start date
1. The problem statement, all variables and given/known data
A friend gave this to me and i have never taken physics could use some help on how to solve this.


2. Relevant equations
Have no clue


3. The attempt at a solution
Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0
 

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gneill

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You need to incorporate the force due to the hanging weight into the second equation.

EDIT: Sorry, the *first* equation! The vertical components.
 
Last edited:

SammyS

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1. The problem statement, all variables and given/known data
A friend gave this to me and i have never taken physics could use some help on how to solve this.


2. Relevant equations
Have no clue


3. The attempt at a solution
Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0
The first equation should be: T1sin42 + T2sin18 - 90 = 0.

Solve the second equation for T1 (in terms of T2). Plug that into the corrected first equation, and solve for T2. Then use that to find T1.
 
T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? Im wanting to learn it thank you for your help.
 

SammyS

Staff Emeritus
Science Advisor
Homework Helper
Gold Member
11,143
911
T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? Im wanting to learn it thank you for your help.
T2(cos18/cos42*sin42+sin18)-90=0

Sorry about not following up.

I get T2=65.93 .
 

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