Solve for the tension in T1 and T2

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Homework Help Overview

The discussion revolves around solving for the tensions T1 and T2 in a physics problem involving forces and angles. Participants are exploring the relationships between these tensions and the forces acting on a system, particularly in the context of equilibrium conditions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to set up equations based on the forces acting on the system, including vertical and horizontal components. There is a focus on correcting initial equations and incorporating additional forces, such as the weight of a hanging object.

Discussion Status

Some participants have provided guidance on how to adjust the equations to include the weight and have suggested methods for solving for T1 and T2. Multiple interpretations of the problem and approaches to the solution are being explored, with no explicit consensus reached yet.

Contextual Notes

There is a mention of the original poster's lack of physics background, which may influence their understanding of the problem setup and equations. Additionally, the discussion includes corrections to initial attempts, indicating a learning process in progress.

lilgen
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Homework Statement


A friend gave this to me and i have never taken physics could use some help on how to solve this.


Homework Equations


Have no clue


The Attempt at a Solution


Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0
 

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You need to incorporate the force due to the hanging weight into the second equation.

EDIT: Sorry, the *first* equation! The vertical components.
 
Last edited:
lilgen said:

Homework Statement


A friend gave this to me and i have never taken physics could use some help on how to solve this.


Homework Equations


Have no clue


The Attempt at a Solution


Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0

The first equation should be: T1sin42 + T2sin18 - 90 = 0.

Solve the second equation for T1 (in terms of T2). Plug that into the corrected first equation, and solve for T2. Then use that to find T1.
 
T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? I am wanting to learn it thank you for your help.
 
lilgen said:
T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? I am wanting to learn it thank you for your help.

T2(cos18/cos42*sin42+sin18)-90=0

Sorry about not following up.

I get T2=65.93 .
 

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