# Solve for the tension in T1 and T2

#### lilgen

1. The problem statement, all variables and given/known data
A friend gave this to me and i have never taken physics could use some help on how to solve this.

2. Relevant equations
Have no clue

3. The attempt at a solution
Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0

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#### gneill

Mentor
You need to incorporate the force due to the hanging weight into the second equation.

EDIT: Sorry, the *first* equation! The vertical components.

Last edited:

#### SammyS

Staff Emeritus
Homework Helper
Gold Member
1. The problem statement, all variables and given/known data
A friend gave this to me and i have never taken physics could use some help on how to solve this.

2. Relevant equations
Have no clue

3. The attempt at a solution
Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0
The first equation should be: T1sin42 + T2sin18 - 90 = 0.

Solve the second equation for T1 (in terms of T2). Plug that into the corrected first equation, and solve for T2. Then use that to find T1.

#### lilgen

T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? Im wanting to learn it thank you for your help.

#### SammyS

Staff Emeritus
Homework Helper
Gold Member
T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? Im wanting to learn it thank you for your help.
T2(cos18/cos42*sin42+sin18)-90=0

I get T2=65.93 .

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