Solve For X: 8th Grade Algebra Problem Solving

  • Context: High School 
  • Thread starter Thread starter Sailcat
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Discussion Overview

The discussion revolves around solving algebraic equations, specifically focusing on how to isolate the variable x in various linear equations. The scope includes conceptual understanding and problem-solving techniques relevant to 8th-grade algebra.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Kyle expresses difficulty in solving for x in equations and requests help with specific examples.
  • One participant suggests rearranging the equation to isolate terms involving x on one side and constants on the other, using the example of 14x - 53 - 32x = 73.
  • Another participant provides a step-by-step approach to solving a different equation, 27x + 19 - 39x = -65, and discusses the importance of correctly applying operations to both sides of the equation.
  • A later reply confirms the correctness of the solution process presented by the previous participant.
  • One participant emphasizes the importance of understanding foundational concepts such as additive inverses and the distributive property, noting that these topics may not be covered in a single class.

Areas of Agreement / Disagreement

Participants generally agree on the methods for solving the equations presented, with some confirming the correctness of the steps taken. However, there is no explicit consensus on the overall understanding of the foundational concepts mentioned.

Contextual Notes

The discussion highlights the need for a solid grasp of algebraic principles, which may not have been fully covered in class, leading to confusion in applying them to solve equations.

Who May Find This Useful

This discussion may be useful for 8th-grade students struggling with algebraic equations, as well as educators looking for insights into common student challenges in understanding algebra concepts.

Sailcat
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How Do i Solve For X?

I Was gone the day we did this is class and we just took a unit test. I bombed it and the end of the quarter is in a few days ! I need to pass algebra (I skipped a grade of math) and I don't know this at all !

So if a problem is like:

14x-53-32x=73 and I need to find x, how do I do it ?

or

18-6(5x-8)=-24? how do I do them. People say you solve differently but I don't get how to do either?! Please help me. I'm gunna retake this target soon ! I need all the help I can get. Ow yeah, I'm in 8th grade, so please use words and phrases that I would understand !
Thank You So Much ! (those arn't homework, just random problems I found).

~Kyle
 
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You want to get your problem to be something like "Ax = b". For your first problem, you have numbers not multiplied by x on both sides of your equation. You want to get them all to one side. If you add 53 to both sides, you will have 14x - 53 + 53 - 32x = 73 + 53.

Now, on the left, the 53's cancel and on the right, it adds to 73 so you have 14x - 32x = 126. Simplify the left side to get -18x = 126. Now you have something that looks like "Ax = b". Simplify divide both sides by -18 and you'll get what x is. Other problems follow similarly to that idea.
 


ok I am following you, but what it its like 27x+19-39x=-65

so you subtract 19 from 19 and -65 and get
27x plus or minus? because its 27x + 19 - 39x?
if its minus then 27x-39x=-84
then do 27-39 and get -12x=-84
then do -12x/-12, and -84/-12. To get 7? am I right?
 


That's right.
To put it simply, the + goes with the 19, the - goes with 39x.
 


omg thank you guys
 


The day when your teacher discusses additive inverses, commutataive property of addition for equality, the distrubutive property, and multiplicative inverses, is the day you do not want to miss. Usually, those will not be taught all in one single class meeting. They might be presented in one meeting as an overview, but studying them will be done through several class meetings among many homework assignments of exercises.
 

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