Solve for 'x' (with 4 variables and 1 equation)

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SUMMARY

The discussion focuses on solving the equation ac + bc = (a - c)(a + b) - xabcd^2 for the variable x. Participants explored various factoring techniques, including the difference of two squares, but encountered challenges in simplifying the equation. The key takeaway is the transformation of the equation into a more manageable form, specifically a = b - cx, which allows for isolating x. The discussion emphasizes the importance of correctly interpreting and rewriting equations to facilitate solving for variables.

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Homework Statement


[tex]ac + bc = (a - c)(a + b) - xabcd^2[/tex]

Homework Equations


Various factoring rules (difference of two squares, etc.)

The Attempt at a Solution


I got it expanded to:

[tex]ac + bc = a^2 + ab - ac - bc - xabcd^2\\0 = a^2 + ab - 2ac - bc - bd - xabcd^2[/tex]

I tried factoring different ways, but it didn't really get me anywhere, and there aren't any "special" factoring rules that I can identify immediately here.

Never mind, I wrote down the problem incorrectly
 
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PhizKid said:

Homework Statement


[tex]ac + bc = (a - c)(a + b) - xabcd^2[/tex]

Homework Equations


Various factoring rules (difference of two squares, etc.)


The Attempt at a Solution


I got it expanded to:

[tex]ac + bc = a^2 + ab - ac - bc - xabcd^2\\0 = a^2 + ab - 2ac - bc - bd - xabcd^2[/tex]

I tried factoring different ways, but it didn't really get me anywhere, and there aren't any "special" factoring rules that I can identify immediately here.

Never mind, I wrote down the problem incorrectly

Think of this:
What if you were asked to make x the subject (in other words, solve for x by putting it alone on one side of the equation) in the equation

[tex]a=b-cx[/tex]

Can you solve this?
 

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