Solve for z: 2.3(1.2)^5z = 3(4.1)^z

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Homework Help Overview

The problem involves solving the equation 2.3(1.2)^(5z) = 3(4.1)^z, which falls under the subject area of algebra and logarithmic properties.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of logarithmic properties to simplify the equation. The original poster attempts to manipulate the equation by dividing and applying logarithms but questions the validity of their results. Others suggest using logarithmic expansion rules to clarify the approach.

Discussion Status

The discussion reflects differing opinions on whether the equation has solutions. Some participants assert that there are no solutions, while others believe a solution exists and encourage revisiting the logarithmic properties. There is an ongoing exploration of the reasoning behind these positions.

Contextual Notes

Participants are considering the implications of using logarithms and whether complex solutions might be relevant. There is uncertainty regarding the correctness of the original poster's calculations and assumptions.

silentsaber
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Homework Statement



2.3(1.2)^5z = 3(4.1)^z solve for z

Homework Equations



the properties of logarithm

The Attempt at a Solution


okay I first divided the 3 with 2.3 and got 1.304 then i brough the 5z and the z down which gives me 5z log(1.2)=1.304 z log(4.1) then i plugged log of 1.2 and 4.1 into the calculator and got .079 and .613 which makes the equation 5z(.079)=1.034z(.613) i then distributed and got .395z=.8z which doesn't give me an answer is the answer no solutions or did i do sumthing wrong?
 
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Hint: log( A B^z ) = log(A) + log(B^z) = log(A) + z log(B)
 
silentsaber said:
...which doesn't give me an answer. Is the answer that there are no solutions or did I do something wrong?

Yes, there are no solutions to this equation. Unless you used z because you want complex solutions, in which case the properties of logarithms aren't the same.
 
qntty said:
Yes, there are no solutions to this equation.

There is most definitely a solution to this equation. Take giant_bog's advice in using that log expansion rule.
 
meiso said:
There is most definitely a solution to this equation. Take giant_bog's advice in using that log expansion rule.

You are correct. My mistake.
 

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