Solve Friction Problem: Find Force P on 20kg Block on 30° Incline

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Homework Help Overview

The problem involves a 20-kg block resting on a 30-degree incline, with a coefficient of static friction of 0.25. The objective is to determine the smallest force P required to initiate sliding up the incline.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss using x and y components to analyze forces acting on the block. One participant expresses confusion over having two equations with three unknowns, questioning how to solve for the normal force affected by the applied force. Others suggest that varying the angle θ could yield different values for P and N, prompting further exploration of how θ impacts the solution.

Discussion Status

The discussion is ongoing, with participants exploring the implications of varying the angle θ and its effect on the values of P and N. Some guidance has been offered regarding the relationship between the equations and the minimum value of P, but no consensus has been reached on the best approach to take.

Contextual Notes

Participants are considering the assumption that θ must be at least 30 degrees, as the block is not being pulled into the ramp. This assumption is under discussion but remains unverified.

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Homework Statement


a 20-kg block rests on a 30 degree incline. knowing that the coefficient of static friction is 0.25, determine the magnitude and direction of the smallest force P required to cause the block to start sliding up the incline.

Figure.jpg


Homework Equations



F = ma

The Attempt at a Solution



I'm trying to solve it using x and y components. For this example, I consider the X direction to be straight up the ramp, and the y to be in the direction of the normal force. The problem is I have 2 equations and ?3? unknowns. How can I solve for Normal force if the normal force is being affected by the pull in the y direction. I've tried to solve this problem many times with no luck. Can someone point me in the right direction?
My teacher told me it would be much easier to solve this using a force Triangle, but I would prefer to use this method. If there were some rule, saying the angle is so-so, because that leads to the least pull this would be a very simple problem.

F_x = Pcos(θ) - mgsin(30) - F_s
F_y = Psin(θ) - mgcos(30) + N
F_s = μN
 
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Hi Patdon10! :smile:
Patdon10 said:
The problem is I have 2 equations and ?3? unknowns.

That's not a problem … it's an opportunity! :wink:

For any value of θ, those equations give you definite values of P and N.

Now choose the minimum value of P. :smile:
 
so I can literally plug in any value for θ and get the values of P and N? If I'm understanding what you're saying...any value of θ will always give the same value of P and N or will the numbers vary and I just need to play with it until I get the lowest value of P?

Is it fair to assume that θ has to be At Least 30 degrees because it's not being pulled into the ramp?
 
Hi Patdon10! :smile:

(just got up :zzz: …)
Patdon10 said:
so I can literally plug in any value for θ and get the values of P and N? If I'm understanding what you're saying...any value of θ will always give the same value of P and N or will the numbers vary and I just need to play with it until I get the lowest value of P?

They'll vary …

it'll be something like P = cosθ + sinθ, which you'll have to minimise. :wink:
Is it fair to assume that θ has to be At Least 30 degrees because it's not being pulled into the ramp?

Yeah, I suppose so … but does it save any time? :blushing:
 

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