Solve Fun Power Question: Frictional Force & Velocity

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Homework Statement


Found a pretty fun question on power from one of my friends old physics exams just wanted to see if I was doing it right so far.

The Attempt at a Solution


So the first thing I did was draw a free body diagram and used Newtons Second law so

ƩFx: F - (250 + 0.7v^2) - mgsin10 = ma

Says that the driving force F must overcome the frictional force, so then ma = 0 and F = 250 + 0.7v^2 + mgsin10. A little stumped here, I am trying to find out the velocity, but I have two unknowns and one equation (please don't give me the answer, I want to solve it myself)!
 
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Hi Panphobia! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)
Panphobia said:
… ƩFx: F - (250 + 0.7v^2) - mgsin10 = ma

Says that the driving force F must overcome the frictional force, so then ma = 0 and F = 250 + 0.7v^2 + mgsin10. A little stumped here, I am trying to find out the velocity, but I have two unknowns and one equation …

I'm confused … the question says a = 1 and v = 27. :confused:
 
But that is initial, the v is always changing, and in my head I was thinking that there is a maximum velocity because of the air resistance. Oh my was I overthinking that? But anyway I was actually talking about deriving an expression for the power P that is required to drive the wheels. The other part is pretty easy.
 
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Then F = 1150 + 250 + 0.7(27)^2 + (1150)(9.8)sin10
P = Fv
P = 3867.3*27
= 104 kW or 140 hp

Deriving would just be without numbers right?
 
Panphobia said:
Then F = 1150 + 250 + 0.7(27)^2 + (1150)(9.8)sin10
P = Fv
P = 3867.3*27
= 104 kW or 140 hp

(i haven't checked your calculations, but …)

yes, those equations look correct :smile:
Panphobia said:
… I was actually talking about deriving an expression for the power P that is required to drive the wheels.
Deriving would just be without numbers right?

an expression would be without numbers, yes :wink: