Solve Heat Transfer Homework: Find Constant K in kW/min

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SUMMARY

The discussion focuses on solving a heat transfer homework problem involving Refrigerant 22 in a rigid closed tank. The energy transfer occurs at a constant rate of 0.1 kW, and the goal is to determine the constant K in the heat transfer equation Q = -Kt. After 20 minutes, the refrigerant's state changes from p1=0.9 MPa, u1=232.92 kJ/kg to p2=1.2 MPa, u2=276.7 kJ/kg. The constant K is derived using the equation K = (-2Q)/(t^2), where Q is the total heat transfer calculated as -76.25 kJ.

PREREQUISITES
  • Understanding of thermodynamics, specifically heat transfer principles.
  • Familiarity with the properties of Refrigerant 22.
  • Knowledge of integral calculus for solving heat transfer equations.
  • Experience with energy balance calculations in closed systems.
NEXT STEPS
  • Study the derivation of the heat transfer equation Q = -Kt in thermodynamics.
  • Learn about the properties and behavior of Refrigerant 22 under varying pressures.
  • Explore integral calculus applications in thermodynamic processes.
  • Review energy balance techniques in closed systems for better understanding.
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, particularly those tackling heat transfer problems in closed systems, as well as educators looking for practical examples of energy transfer calculations.

jdawg
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Homework Statement


One kg of Refrigerant 22 initially at p1=0.9 MPa, u1=232.92 kJ/kg, is contained within a rigid closd tank. The tank is fitted with a paddle wheel that transfers energy to the refrigerant at a constant rate of 0.1kW. Heat transfer from the refrigerant to its surroundings occurs at a rate Kt, in kW, where K is a constant, in kW per minute, and t is time, in minutes. After 20 minutes of stirring, the refrigerant is at p2=1.2MPa. u2=276.7kJ/kg. Neglect kinetic and potential energy. Determine the value of the constant K appearing in the given heat transfer relation in kW/min.

Homework Equations

The Attempt at a Solution


I've already found the work to be W= -120 kJ and the heat to be Q= -76.25 kJ

What I'm struggling with is how to find the constant K.
Bounds are from 0 to 20 minutes.
Q=∫ Qdt
=∫-Kt dt
=-kt2/2

And now I'm stuck, I'm not sure what to do at this point.
The next step shows K=(-2Q)/(t2) I have no idea how they got this.
 
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jdawg said:
Q=∫ Qdt
=∫-Kt dt
=-kt2/2

And now I'm stuck, I'm not sure what to do at this point.
The next step shows K=(-2Q)/(t2) I have no idea how they got this.
It looks like just a rearrangement of your last equation, no?
 
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Likes   Reactions: jdawg
Haha oh my god, thanks! I forgot it was equal to Q :P
 

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