# Solve Hooke's Law Problem: Spring Constant & Compression

• MozAngeles
In summary, the conversation discusses a problem involving a 60 kg driver getting into an empty taptap, which compresses the springs by 0.02 m. The effective spring constant of the spring system is calculated to be 2.94*10^4 using the formula F=kx. After the taptap is loaded with 25 people, 3 goats, 5 chickens, and 25 kg of bananas, the springs compress further. The correct value for the compression is found to be .5328, after using the formula F=kx and considering the total mass of the taptap. The conversation also highlights the importance of solving for the value of k before using the formula.
MozAngeles

## Homework Statement

A 60 kg driver gets into an empty taptap to start the day's work. The springs compress 0.02 m. What is the effective spring constant of the spring system in the taptap?
using F=kx I got 2.94*10^4
Then
After driving a portion of the route, the taptap is fully loaded with a total of 25 people with an average mass of 60 kg per person. In addition, there are three 15 kg goats, five 3 kg chickens, and a total of 25 kg of bananas on their way to the market. Assume that the springs have somehow not yet compressed to their maximum amount. How much are the springs compressed?
I used the formula F=kx, solving for x, but i got the wrong answer (1.80*10^4) the answers turns out to be .5328. I just don't know how to get there.
For F i just multiplied each set of things times the number there was of them times the mass (kg) times 9.8 m/s^2 to get Newtong for each, then i divided that by the constant i found previously.

## The Attempt at a Solution

I used the formula F=kx, solving for x, but i got the wrong answer (1.80*10^4) the answers turns out to be .5328. I just don't know how to get there.
For F i just multiplied each set of things times the number there was of them times the mass (kg) times 9.8 m/s^2 to get Newtong for each, then i divided that by the constant i found previously.

The work done by man in compressing the spring is equal to the gain in elastic energy of the spring.

mgx=0.5kx^2
solve this and you will get value of k
Rest is done using same equation.

i realized all i was doing wrong was the total mass of the taptap thanks anyways..

## 1. What is Hooke's Law?

Hooke's Law states that the force required to compress or extend a spring is directly proportional to the distance it is stretched or compressed. This relationship can be represented by the equation F = -kx, where F is the force, k is the spring constant, and x is the displacement.

## 2. How do I calculate the spring constant?

The spring constant, k, can be calculated by dividing the applied force by the displacement. This can be represented by the equation k = F/x. It is important to ensure that the units for force and displacement are consistent, typically in newtons (N) and meters (m) respectively.

## 3. What is the unit for spring constant?

The unit for spring constant, k, is newtons per meter (N/m). This unit represents the amount of force required to stretch or compress a spring by one meter.

## 4. How do I solve for the compression of a spring using Hooke's Law?

To solve for the compression of a spring using Hooke's Law, you will need to know the applied force and the spring constant. Once you have these values, you can rearrange the equation F = -kx to solve for x, which represents the compression of the spring.

## 5. Can Hooke's Law be applied to all types of springs?

Hooke's Law can be applied to most types of springs, as long as they follow a linear relationship between force and displacement. However, it may not be accurate for very large displacements or for materials that do not behave elastically.

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