Solve Ideal Diode Problem: V & I Calculation

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SUMMARY

The discussion centers on solving the Ideal Diode Problem involving two diodes, D1 and D2, to determine the voltage (V) and current (I) in the circuit. The initial assumption that D1 is on and V equals 0 is incorrect. Participants suggest removing D2 from the circuit to analyze the voltages at its nodes and determine its bias state. The correct approach involves testing both scenarios: D2 being forward-biased and non-conducting to find a consistent solution for I.

PREREQUISITES
  • Understanding of ideal diode behavior and biasing conditions
  • Basic circuit analysis techniques, including node voltage analysis
  • Familiarity with forward and reverse bias concepts in diodes
  • Knowledge of Kirchhoff's laws for circuit analysis
NEXT STEPS
  • Study the principles of ideal diode operation and characteristics
  • Learn about node voltage analysis in electrical circuits
  • Explore forward and reverse bias conditions in semiconductor devices
  • Review Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) applications
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Electrical engineering students, circuit designers, and anyone involved in analyzing diode circuits will benefit from this discussion.

steveH
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Hi,

I am stuck trying to work out a problem involving two ideal diodes.

http://img200.imageshack.us/img200/668/idealdiodev.jpg

I need to find V and I. Aswell as which diode is on and off.

I have tried to solve it by assuming d1 is on and hence V is 0 but i can't get the right answers no matter what formula I try.

Any help would be greatly appreciated.

thanks
-Steve
 
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Remove D2 from the circuit. Work out the voltages at the nodes where D2 was connected. Decide whether D2 would be forward or reverse biased. Proceed from there.
 
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steveH said:
I have tried to solve it by assuming d1 is on and hence V is 0 ...

Um, no, you can't conclude V is 0 from assuming D1 acts as a short.

Using the D1-is-on assumption, try solving the problem for both D2-is-on and D2 is non-conducting. See which assumption gives a consistent solution:


If D2 is on, do you get a positive value for the current I? (I.e., the diode is forward-conducting)​
or
If D2 is non-conducting, do you get a higher voltage on the left side than the right? (I.e., it is reverse-biased)​
 

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