Solve Integration Problem: Volume of Rotor Ring in x-axis

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To find the volume of the solid rotor ring formed by rotating the area between the lines y=x+5 and y=2x+7 around the x-axis, the correct approach involves using the formula for volume, V = ∫[a to b] π[f(x)]² dx. The initial integration provided was incorrect, yielding a volume of 3.5 cubic units instead of the correct 2.5 cubic units. Simply integrating the difference of the two functions does not yield the volume; it only gives the area under one function. The next step is to apply the volume formula using one of the functions to calculate the correct volume.
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Homework Statement



A solid rotor ring is made by rotation round the x-axis the area enclosed between the lines y=x+5 and y=2x+7 between the x-values x=0 and x=1.
Find its volume.

Homework Equations


n/a


The Attempt at a Solution


ytobeintegrated = 2x+7-x-5 \\= x+2\\\int (x=2)dx \\=\left[\frac{x^2}{2}+2x\right](between 1 and 0) \\=3.5 units

What next? I think this is only giving me the area in one plane? Do i just multiply by 360 degrees?
 
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You cannot simply take away the two functions before integration or multiply by 360 degrees. Also, if you integrate any 2-dimensional, cartesian function without any manipulation you will only get the area under that function. So although your integration is correct (though your solution should be 2.5 cubic units not 3.5), the idea is not.

Try using:

Volume \ = \ \int_{a}^{b} \pi f(x)^{2} \ dx
where f(x) is one of the functions.

What do you think is the next step?

The Bob
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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