Solve Isothermal Expansion - Pressure, Volume & Work Explained

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SUMMARY

The discussion focuses on calculating the external work performed during the isothermal expansion of air from an initial pressure of 40 psig and a volume of 8 cu. ft. to a final pressure of 10 psig. The key formula used is W = ∫(P_i to P_f) PdV, which can be simplified using the ideal gas law PV=nRT. It is essential to convert gauge pressure (psig) to absolute pressure (psia) by adding atmospheric pressure, as this affects the calculations. The pressure ratio P_f/P_i is crucial for determining the work done during the expansion.

PREREQUISITES
  • Understanding of the ideal gas law (PV=nRT)
  • Knowledge of pressure units (psig vs. psia)
  • Familiarity with calculus, specifically integration
  • Basic concepts of thermodynamics, particularly isothermal processes
NEXT STEPS
  • Learn how to convert between gauge pressure and absolute pressure
  • Study the derivation of the work done in isothermal processes
  • Explore the implications of the ideal gas law in real-world applications
  • Investigate the use of MKS (Meter-Kilogram-Second) units in thermodynamic calculations
USEFUL FOR

Students and professionals in engineering, particularly those specializing in thermodynamics, mechanical engineers, and anyone involved in gas expansion calculations.

shawn100
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If air has a pressure of 40 psig and a volume of 8 cu. ft. expands isothermally to a pressure of 10 psig, find the external work performed during the expansion. How do I do this, do I first have to change 40 psig to psia, and how do I do that? This question has me lost! Any help appreciated, even a formula for me to understand it would help. thank you
 
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shawn100 said:
If air has a pressure of 40 psig and a volume of 8 cu. ft. expands isothermally to a pressure of 10 psig, find the external work performed during the expansion. How do I do this, do I first have to change 40 psig to psia, and how do I do that? This question has me lost! Any help appreciated, even a formula for me to understand it would help. thank you
Use PV=nRT.

If T is constant then P_iV_i = P_fV_f. So you can work out what the final volume is.

The work is:

W = \int_{P_i}^{P_f} PdV = \int_{V_i}^{V_f} \frac{nRT}{V}dV

You have to work out that integral (hint: \frac{d}{dV}ln V = 1/V) and plug in the initial and final volumes.

You don't have to do any conversions. You just need the pressure ratio P_f/P_i.

AM

[edit: this last comment is not quite correct. You do have to work out nRT = P_iV_i which means you have to do a conversion. PSIA is absolute pressure in pounds/in^2, which means you have to include atmospheric pressure. PSIG is gauge pressure, which is 1 atm less than actual. It is easier to work in MKS. I would convert to MKS and then convert back.]

AM
 
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