- #1

MysticDream

- 49

- 3

Now, if I use a simple pressure-area-volume formula to calculate work at the constant pressure of 10 psig and use that same displacement volume of 44.9, the total work done is about 50.7 joules. This is almost half the work done with the first formula and it's not even adiabatic expansion, but constant pressure (isobaric).

How is this possible?