Solve KE, PE and Work for Block Sliding Down Friction-Less Incline

  • Thread starter Thread starter zzoo4
  • Start date Start date
  • Tags Tags
    Work
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
17 replies · 3K views
zzoo4
Messages
42
Reaction score
0

Homework Statement


How do you solve this??

A 2kg block starts from rest slides down a friction-less incline plane that is at angle of 20degree with the horizontal. At a certain point on the incline, the speed of the block is 9m/s.

1.What is the vertical distance the block has traveled??
2.What is the work done by gravity as the block moves the vertical distance you found??





Homework Equations



Work= Force x Displacement
KE= .5mv^2
PE= mgh

The Attempt at a Solution



for number 1, I know that my PEf nd KEi =0.
So i set PEi and KEf equal to each other.
PEi=KEf.
So what i did was mgh=.5*m*v^2.
m's cancel out.

so 9.8h=.5v^2.
.. This is where i am stuck.. I am not sure if i am doing right.. But how do i find v which is velocity?
 
Physics news on Phys.org
I think it gives the velocity in the problem statement. (actually the speed)
 
zzoo4 said:
...

for number 1, I know that my PEf nd KEi =0.
So i set PEi and KEf equal to each other.
PEi=KEf.
So what i did was mgh=.5*m*v^2.
m's cancel out.

so 9.8h=.5v^2.
.. This is where i am stuck.. I am not sure if i am doing right.. But how do i find v which is velocity?
Solve your last equation for h.
 
You should be able to solve it. What is v ?
 
the speed is 9.. Okay i got #1 which is 4.14 m..

But cannot find the work done by gravity??
 
What's the force of gravity, on the block?
 
Why 4 kg ?

(2kg )(9.8 N/kg) = ?

The weight!
 
Oh sorry. I thought the mass was 4kg.
so its actually.

2kg * 9.8 n/kg = 19.6 N.

So what now??
 
Work= Force x Displacement (sort of)

Actually: Work= Force x (the component of Displacement that's in the direction of the force)

the component of Displacement that's in the direction of the force = h