Solve Log Law Problems Homework Statement

  • Thread starter Thread starter AbsoluteZer0
  • Start date Start date
  • Tags Tags
    Law Log
Click For Summary
SUMMARY

The discussion focuses on solving logarithmic expressions using logarithm laws. Participants confirmed that the first problem simplifies correctly to log_{10}(\frac{AB}{C}). For the second problem, the correct simplification is log_{10}(\frac{X^{0.5}}{16}), applying the property log_b(x^n) = n log_b(x). The third problem simplifies to log_{10}(N^2X^3), demonstrating the application of logarithmic properties effectively.

PREREQUISITES
  • Understanding of logarithm laws, specifically log_a(xy) = log_a(x) + log_a(y) and log_a(\frac{x}{y}) = log_a(x) - log_a(y).
  • Familiarity with the property log_b(x^n) = n log_b(x).
  • Basic algebraic manipulation skills.
  • Knowledge of the base-10 logarithm (log_{10}).
NEXT STEPS
  • Study advanced logarithmic identities and their applications in problem-solving.
  • Practice simplifying logarithmic expressions with varying bases.
  • Explore the relationship between logarithms and exponential functions.
  • Learn about logarithmic scales and their real-world applications.
USEFUL FOR

Students studying algebra, educators teaching logarithmic concepts, and anyone needing to solve logarithmic equations efficiently.

AbsoluteZer0
Messages
124
Reaction score
1

Homework Statement

Write as a single logarithm:

Homework Equations



Logarithm Laws:

log_a(xy) = log_a(x) + log_a(y)

log_a(\frac{x}{y}) = log_a(x) - log_a(y)
___________

Problem Set:

log_{10}A + log_{10}B - log_{10}C

\frac{1}{2}logX - 2log4

2logN + 3logX

The Attempt at a Solution



I simplified the first question to log_{10}(\frac{AB}{C}) Am I correct?

I wasn't sure about how to approach the second question. I multiplied \frac{1}{2} by X and 2 by 4 and simplified as follows:

log_{10}{\frac{1}{2}X} - log_{10}8

to get log_{10}(\frac{0.5x}{8})

I'm not sure if this is correct though.

If it is wrong, how would I solve it correctly?

For the third problem, I solved it to:

log_{10}[ (2n)(3x) ]

Thanks,
 
Physics news on Phys.org
Your AB/C is correct.

For the 1/2 log X you haven't listed the loglaw for it which is:

C * log (x) = log (x^C)

given that rework your answer.
 
AbsoluteZer0 said:
I simplified the first question to log_{10}(\frac{AB}{C}) Am I correct?

Yes..Thats right.

AbsoluteZer0 said:
I wasn't sure about how to approach the second question. I multiplied \frac{1}{2} by X and 2 by 4 and simplified as follows:

log_{10}{\frac{1}{2}X} - log_{10}8

to get log_{10}(\frac{0.5x}{8})

I'm not sure if this is correct though.

If it is wrong, how would I solve it correctly?

For the third problem, I solved it to:

log_{10}[ (2n)(3x) ]

Thanks,

That is not the correct way .

Use the following property of logarithms : logb(xn) = n logbx.
 
I solved the second one to:

log_{10}\frac{X^{0.5}}{16}

Is this correct?

Thanks
 
AbsoluteZer0 said:
I solved the second one to:

log_{10}\frac{X^{0.5}}{16}

Is this correct?

Thanks

Correct
 
And would the second one be

log_{10}(N^2X^3)?

Thanks
 
AbsoluteZer0 said:
And would the second one be

log_{10}(N^2X^3)?

Thanks

:thumbs:
 
  • Like
Likes   Reactions: 1 person
Thank you very much!
 
dont forget to use the Thanks button to thank everyone.
 
  • Like
Likes   Reactions: 1 person

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 25 ·
Replies
25
Views
3K
Replies
2
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K