Solve Log Question: Find Cube Root of 25 in Base 5

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The problem involves finding the logarithm of the cube root of 25 in base 5. The solution is confirmed to be 2/3, as indicated in the textbook. To derive this, it is shown that the cube root of 25 can be expressed as 25^(1/3), which simplifies to (5^2)^(1/3). Using exponent rules, this further simplifies to 5^(2/3). Thus, the logarithmic equation log base 5 of the cube root of 25 equals 2/3.
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Homework Statement



log base 5 cube root 25 equals what?


Homework Equations



I know that the answer is 2/3 because it is in the back of the book

The Attempt at a Solution



log base 5 = 25 to the 1/3

so 5 to the what = 25 to the 1/3

How do I get 5 to the 2/3 equals 25 to the 1/3? This is the only tough question in this section. :cry:
 
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gabby989062 said:

Homework Statement



log base 5 cube root 25 equals what?


Homework Equations



I know that the answer is 2/3 because it is in the back of the book

The Attempt at a Solution



log base 5 = 25 to the 1/3

so 5 to the what = 25 to the 1/3

How do I get 5 to the 2/3 equals 25 to the 1/3? This is the only tough question in this section. :cry:

write 25 to the 1/3 as 25^(1/3).
but 25=5^2 so 25^(1/3)=(5^2)^(1/3). By your rules about exponents that is equal to 5^(2/3).
 

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