Solve Magnetic Problem: Find Field Magnitude from Radius & Speed

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SUMMARY

The discussion focuses on deriving the expression for the radius of the circular path followed by electrons in a magnetic field, specifically using the equation Fm = q(v × B). Given the speed of the electrons at 5.9 × 106 m/s and a circular path radius of 2.0 cm, the task is to find the magnitude of the magnetic field B. The relevant equations include Rc = mv / qB and T = 2πRc / v. The user encountered difficulties in eliminating the charge q from the equations while maintaining clarity in the derivation process.

PREREQUISITES
  • Understanding of Lorentz force (Fm = q(v × B))
  • Familiarity with circular motion concepts in physics
  • Knowledge of the relationship between centripetal force and magnetic force
  • Basic algebraic manipulation skills for solving equations
NEXT STEPS
  • Derive the expression for magnetic field B using the formula Rc = mv / qB
  • Explore the concept of cyclotron motion and its implications on particle dynamics
  • Study the relationship between frequency, period, and magnetic field strength in circular motion
  • Learn about the implications of charge and mass on the radius of circular paths in magnetic fields
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Students studying electromagnetism, physics educators, and anyone interested in the dynamics of charged particles in magnetic fields.

bidhati
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Homework Statement



A stream of 100 eV electrons, each with speed v = 5.9 × 106 ms−1, traveling horizontally along the x-axis in the positive x-direction enters a region pervaded by a uniform magnetic field B. The electrons then describe a circle with radius R in the horizontal xy-plane, circulating anticlockwise as viewed from above.
Starting from the equation Fm = q(v × B), derive an expression for the
radius, R, of the circular path followed by the electrons. If R = 2.0 cm, find the magnitude, B, of the uniform magnetic field.

Homework Equations



1. Fm = q(v x B)

2. Rc = mv / qB

3. T = 2 pi mv /vqB = 2 pi Rc / v =2 pim / qB

4. Fm = q v b sin Theta



The Attempt at a Solution


ok the only known variables I have are
v = 5.9 × 106 ms−1
Rc = 2.0

and I know from the next question on my paper that fromthe expression derived I have to evaluate T so therefore T v and Rc must be in the final equation.

The problem I am getting is trying to eliminate q
I started by eliminating Fm by setting equations 1 and 4 =
but the q on the left is magnitude q and the q on the right is not. so I am getting confused now, have rearranged all the equations and substiuting each different variable but the more I carry on I just end up with a HUGE equation I get the feeling that I am making this way too complicated for myself also am I correct in thinking that as the electron showed cyclotronic motion that theta is 90 degrees? help please?
 
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The magnetic force is behaving as centripetal force required to make the path circular.
 

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