Solve Matrix Proof: Q36 + Bonus Q38

  • Thread starter Thread starter Gameowner
  • Start date Start date
  • Tags Tags
    Matrix Proof
Click For Summary
SUMMARY

The discussion focuses on solving matrix proofs related to questions 36 and 38, specifically utilizing the properties of rotation matrices and the identity matrix. It is established that B^8 equals the identity matrix, leading to the conclusion that B^2001 simplifies to I*B. The challenge lies in determining an appropriate angle Theta that allows the application of question 38's formulas to effectively solve question 36.

PREREQUISITES
  • Understanding of rotation matrices and their properties
  • Familiarity with matrix exponentiation and identity matrices
  • Knowledge of product-to-sum formulas in trigonometry
  • Basic concepts of angles in radians, specifically pi and pi/2
NEXT STEPS
  • Explore the properties of rotation matrices in detail
  • Research matrix exponentiation techniques and their applications
  • Study product-to-sum formulas in trigonometry
  • Investigate the implications of using different angles in matrix transformations
USEFUL FOR

Students and educators in linear algebra, particularly those focusing on matrix theory and proofs, as well as anyone interested in advanced mathematical problem-solving techniques.

Gameowner
Messages
43
Reaction score
0

Homework Statement



Questions on it's own are relatively simple, however, there is a bonus question which asks ''with a right choice of Theta, show how you can do question 36 easily with question 38''



Homework Equations





The Attempt at a Solution



Attempting question 36, it is known that B^8 is the identity matrix, so B^2001 is I*B.

Question 38 is just using some product to sum formulas etc, but I'm stuck as to how I apply question 38 to solve 36? my initial guess is Theta=pi or pi/2?

Any hints, tips would be much appreciated.
 

Attachments

  • 36.jpg
    36.jpg
    3.4 KB · Views: 386
  • 38.jpg
    38.jpg
    7 KB · Views: 395
Physics news on Phys.org
so try and find an angle \theta such that A(\theta) = B

A is a rotation matrix, and aplying A^2 rotates by twice the angle, so have a think what 2001 times the angle is for B
 

Similar threads

Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
14K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K