Solve Parallelepiped Transformation Problem to Rectangular Box

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  • Thread starter Thread starter squenshl
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Discussion Overview

The discussion revolves around the problem of transforming a parallelepiped into a rectangular box by making specific cuts and rearranging the pieces. It explores the geometric properties of the shapes involved and the implications of volume calculations.

Discussion Character

  • Exploratory
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions how to start with a parallelepiped, cut four faces vertically, and rearrange the pieces to form a rectangular box, emphasizing the relationship between volume and base area.
  • Another participant points out that the volume of a parallelepiped is already defined as the area of the base times the height, suggesting that the transformation may not be necessary.
  • There is a clarification regarding the volume formula, with a participant stating it as a.(bxc), which is further refined to |a.(bxc)| to indicate positive volume.
  • A later reply introduces a hypothetical scenario involving a loaf of bread or a paper model, suggesting a practical approach to the problem.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of transforming the parallelepiped into a rectangular box, with some asserting that the volume relationship is already satisfied, while others explore the practical aspects of the transformation.

Contextual Notes

The discussion does not resolve the assumptions regarding the nature of the cuts or the specific conditions under which the transformation is to be achieved. The implications of volume calculations and geometric properties remain open to interpretation.

squenshl
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I was just wondering how I can start out with a parallelepiped only cutting 4 faces vertically, at right angles to the edges I cut through & rearrange the pieces so that I can get rectangular box so that the volume is the area of the base times the height.
 
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squenshl said:
I was just wondering how I can start out with a parallelepiped only cutting 4 faces vertically, at right angles to the edges I cut through & rearrange the pieces so that I can get rectangular box so that the volume is the area of the base times the height.

If this is a puzzle where you are trying to re-arrange the pieces to form a rectangular box, I can't help you. Are you aware the volume of a parallelepiped is the already the area of the base times the height?
 


LCKurtz said:
If this is a puzzle where you are trying to re-arrange the pieces to form a rectangular box, I can't help you. Are you aware the volume of a parallelepiped is the already the area of the base times the height?

Actually the volume of a parallelpiped is a.(bxc)
 


jav said:
Actually the volume of a parallelpiped is a.(bxc)

You mean |a.(bxc)|.
 


Yup, no negative volumes here. :)
 


How could you do it if you had say a loaf of bread or a paper model.
 

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