Solve Physics Problem: Jet Aircraft Launch from Carrier

Click For Summary
SUMMARY

The discussion focuses on solving a physics problem involving the acceleration of a jet aircraft launching from an aircraft carrier over a 94-meter track in 2.5 seconds. The initial incorrect approach used the equation V=V0 + at, leading to a miscalculation of 235 m/s. The correct method involves using the distance formula d = V0 t + (1/2) a t², resulting in an acceleration of 30 m/s². Participants emphasized the importance of clearly stating the problem and using the correct units for speed and distance.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Familiarity with units of measurement (meters, seconds)
  • Ability to manipulate algebraic equations
  • Knowledge of acceleration concepts
NEXT STEPS
  • Study kinematic equations in detail, focusing on their applications
  • Practice problems involving acceleration and distance calculations
  • Learn about the implications of unit conversions in physics
  • Explore real-world applications of physics in aviation and engineering
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in the principles of motion and acceleration in aviation contexts.

prokoro
Messages
5
Reaction score
0
Hello,

I'm doing this problem; a jet aircraft bein launch from an aircraft carrier acceleration from the rest along a 94m track for 2.5sec?

The problem is my answer is different from book

I am using the equation V=V 0 + at

V=94m
T=2.5sec

V=0+94m(2.5sec)=235m/s

I know this answer is wrong I suppose to be looking for the acceleration of the aircraft assuming constant.

I even tried to work this problem with the equation
V^2=V^20+2a(x-x)

thank-you
 
Physics news on Phys.org
Nevermind the above post

I figured out the correct answer to the problem V^2+V^2/2(x-x).

(2.5s)^2-(0)^2/2(94m)=30m/s
30m/s instead of the above answer
 
I'm glad you finally got it! For future reference, it would be good idea to tell us what the question is! I assume, although you didn't say it, that you are given the final speed and time and are asked what the acceleration is. By the way, you tell us that
V= 94 m which doesn't make sense: "meters" measures distance, not speed. 94 meters is the length of the track so you need to use the distance formula: d= 94= V0 t+ (a/2) t2.
V0= 0 and t= 2.5 so you can solve for a.
 

Similar threads

Replies
3
Views
3K
Replies
23
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
7K