Solve Physics Problem: Urgent Cessna-182 Plane Mass 1290kg Glide Angle

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SUMMARY

The discussion focuses on solving a physics problem involving a Cessna-182 airplane with a mass of 1290 kg experiencing engine failure and gliding at a speed of 139 km/h. The glide angle was calculated to be 5.76 degrees, and the lift force was determined to be 12654.9 N. Additionally, the gravitational potential energy loss rate was addressed, emphasizing the relationship between mass, gravitational acceleration, and altitude change.

PREREQUISITES
  • Understanding of basic physics concepts such as forces and energy
  • Familiarity with the equations of motion, specifically F = mg cos(theta)
  • Knowledge of gravitational potential energy, U = mgy
  • Basic trigonometry for calculating angles
NEXT STEPS
  • Study the derivation and application of the lift force equation in aviation
  • Learn about the principles of glide ratio and glide angle in aerodynamics
  • Explore the effects of drag force on aircraft performance during gliding
  • Investigate the calculations for energy conservation in flight dynamics
USEFUL FOR

Aerospace engineering students, physics enthusiasts, and pilots interested in understanding the dynamics of aircraft performance during engine failure scenarios.

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Homework Statement


A fully loaded Cessna-182 airplane of mass 1290kg has an engine failure when flying with an airspeed of 139 km/h at an altitude of 2710 m on a calm day. it then glides at a constant glide angle(which is the direction of flight below the horizontal) towards a safe landing at this constant speed of 139km/h experiencing a drag force of 1270 N that opposes the directin in which the plane is moving.
i) Find the magnitude of:

a) The glide angle
5.75 degrees

b) The lift force.
12654.9 N

c) The rate at which the loaded plane is losing gravitational potential energy[/B]

ii) Suppose the pilot instead had managed to get the airplane engine started such that he was able to apply full throttle and the airplane climbed along a straight line angled above the horizontal so that it gained altitude at a steady rate of 5.61 m/s. Assuming he was again flying with an airspeed of 139km/h determine:

i) the flight angle above the horizontal the plane is flying.

The Attempt at a Solution



I have already found the glide angle and lift force using F = mg cos(theta)
The glide angle is 5.76 degrees
The lift force is 12654.9 N
 
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Hi sid88,

The gravitational potential energy for this problem is U=mgy. The rate of change of U is the rate of change of mgy. Since m and g are constants, can you find the rate of change of y?

Once you find that, a quick multiplication will give you the rate of change of mgy.
 

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