Solve Pith Ball Charge: Equal Charges on Two Balls

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The discussion revolves around calculating the charge on two equal pith balls suspended by strings, each with a mass of 12 g and forming an angle of 42.6 degrees with the vertical. The user initially calculated the tension in the strings and the electric force but mistakenly used an incorrect weight value of 117.6 N due to not converting grams to kilograms. After correcting this error, the user aimed to find the charge using the formula Fe = kQ²/r², where r was determined to be 1.6 m.

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Two small pith balls, each of mass m = 12 g, are suspended by 1.2 m fine strings and are not moving. If the angle that each string makes with the vertical is q = 42.6 , and the charges on the two balls are equal, what is that charge (in microC)?

http://img386.imageshack.us/img386/5977/picmd8.th.jpg

I equated the forces in x and y to zero:

Tcos42.6-117.6=0
T=159.76

Tsin42.6+Fe=0
plugging in 159.76
Fe=108

then i used the equation Fe=kQ^2/r^2

i solved for r by doing this:
r=2(1.2sin42.6)
r=1.6 m

I'm not sure if my steps are right. Can someone help me? Thanks in advance!
 
Last edited by a moderator:
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What's tan theta equal to?

Yep, it seems right what you have right now.

tan 42.6 = Electric force / gravitational force


Select to get more hint
 
rootX said:
What's tan theta equal to?

Yep, it seems right what you have right now.




tan 42.6 = Electric force / gravitational force


Select to get more hint

let's a better way to find Fe, which is 108 N. Then plugging it into the equation then solving for Q, the answer I came up with is 178 microC, but the answer is wrong =(
I don't know where I've made a mistake.
 
Hi chukie,

chukie said:
Two small pith balls, each of mass m = 12 g, are suspended by 1.2 m fine strings and are not moving. If the angle that each string makes with the vertical is q = 42.6 , and the charges on the two balls are equal, what is that charge (in microC)?

http://img386.imageshack.us/img386/5977/picmd8.th.jpg

I equated the forces in x and y to zero:

Tcos42.6-117.6=0

The weight of 117.6 N you find here does not look correct to me. (You don't have units here, but your last post indicates that you meant it to be Newtons.) Do you see what went wrong?
 
Last edited by a moderator:
ahhh! i see now! i forgot to convert grams into kg! thanks so much!
 

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