Solve Plane Problem: Find Time & Distance for Dropping Supply Crate

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SUMMARY

The discussion focuses on solving a physics problem involving an airplane dropping a supply crate. The airplane travels at 125 km/h (34.7 m/s) at an altitude of 1001 m. The correct time to drop the crate is calculated as 102.14 seconds before reaching the target, with a horizontal distance of 3544.26 m from the target at the moment of drop. The initial approach to calculating the time using the equation 9.8t=1001 was incorrect, as the proper formula for distance in free fall must be applied.

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  • Understanding of kinematic equations, particularly for free fall.
  • Knowledge of converting units from km/h to m/s.
  • Familiarity with horizontal and vertical motion components in physics.
  • Basic grasp of gravitational acceleration (9.8 m/s²).
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  • Review the kinematic equations for motion under gravity.
  • Learn about projectile motion and its components.
  • Study unit conversion techniques, especially for speed.
  • Explore real-world applications of physics in aviation and supply drops.
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Students studying physics, particularly those focusing on kinematics, as well as educators and anyone interested in practical applications of physics in aviation scenarios.

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Homework Statement


An airplane is traveling at 125km/h at an altitude of 1001m. It is dropping a supply crate on a specified target. Air resistance is ignored.

a.)How many seconds before being directly overhead should the box be dropped to hit the target?

b.)What is the horizontal distance between the plane and the target when the box should be dropped?


Homework Equations


velociy in the X direction=x/t


The Attempt at a Solution


I converted the speed into m/s, which came out to be 34.7m/s, which gave me my two unknowns: 34.7=x/t

I decided to find the time in the y (vertical) direction first, using simply 9.8t=1001. t=102.14 seconds. Since the X and Y direction times are the same, I plugged in the time into 34.7=x/t and solved for x an got 3544.26m

And to clarify my answers a.) 102.14 seconds, b.) 3544.26m

I just want to make sure I followed the correct procedure when solving this problem
 
Last edited:
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leftyguitarjo said:
I decided to find the time in the y (vertical) direction first, using simply 9.8t=1001.
You are saying that y = gt? That's incorrect. (Perhaps you're mixing it up with v = gt.) Find the correct expression for distance as a function of time for a falling body.
 

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