- #1

Humbleness

- 31

- 1

## Homework Statement

A plane is to be used to drop emergency medical supplies (encased in a crash-proof container) to campers in Northern Ontario. The campers are in a clearing. The plane will approach the clearing at an altitude of 150m while flying level at 40m/s.

a) Why can't the pilot wait until the plane is directly over the campsite before dropping the supplies?

b) How far (in meters) ahead of the campsite should the supplies be dropped? Justify your choice.

## Homework Equations

Δd

_{v}= 1/2 aΔt

^{2}- To find how long until the supplies hit the ground.

horizontal displacement = horizontal velocity which is 40m/s x Δt - To find how far horizontally would the supplies travel after being released from the plane

## The Attempt at a Solution

I will first start with b)

So I used the formula:

Δd

_{v}= 1/2 aΔt

^{2}

150m [down] = 1/2 (9.8m/s

^{2}[down]) Δt

^{2}

Δt

^{2}= 150 : 4.9 = √30.6

Δt = 5.5sThen I used the horizontal velocity of 40m/s x 5.5s (the time), to get the answer to horizontal displacement:

40m/s x 5.5s = 220m

So the supplies should be dropped 220m ahead of the campsite. This means that both the plane and the supplies themselves will be at 220m ahead of the campsite at the same time. Am I correct with this part, at least? I would really appreciate a confirmation.

For a) I tried drawing a diagram to show the airplane directly above the campsite, and then tried to draw a triangle, so that perhaps using trigonometry I could find out why the pilot shouldn't drop the supplies when directly above the campsite. But I am still not understanding how to even begin the calculations, using what equation... My main concern is that I am not understanding how to get to the answer to part a. How do I calculate what would happen if the plane dropped the supplies when directly above the campsite? I don't understand.