Solve Polynomial Decomposition: -4x2 + 15x - 8/(x-1)3(x+2) | Step-by-Step Guide

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Homework Help Overview

The discussion revolves around the polynomial decomposition of the expression -4x² + 15x - 8 divided by (x - 1)³(x + 2). Participants are exploring the method of partial fractions to break down this rational function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to set up the partial fraction decomposition but expresses uncertainty about their approach. Some participants confirm the method being used and suggest specific steps to isolate coefficients.

Discussion Status

The discussion is active, with participants providing guidance on how to proceed with the decomposition. There are indications of productive direction, particularly in solving for coefficients by substituting specific values for x.

Contextual Notes

The original poster mentions being new to the topic of partial fractions, indicating a learning context. There is also a reference to the class having just started on this material, which may imply a need for foundational understanding.

js14
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−4x2 + 15x − 8/
(x − 1)3(x + 2)

A/x+2 + B/x-1 + C/(x-1)^2 + D(x-1)^3 =

A(x-1) + B(x+2) + C(x-1)^3 + D(x-1)^2 =

(Ax-A) + (Bx+2B) + (Cx^3-3C^2+Cx-C) + (Dx^2-2Dx+D) =

(Cx^3) + (-3Cx^2+Dx^2) + (Ax+Bx+Cx-2Dx) + (-A+2B-C+D)

I know this isn't finished but I think i when wrong somewhere. can someone help me?
 
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are you trying to do partial fractions?
 
Yes. My class just started on it the other day and I think I am getting close but I am still a little confused.
 
your first couple of steps look good .
[tex] \frac{-4x^2+15x-8}{(x-1)^3(x+2)}=\frac{A}{x+2}+\frac{B}{x-1}+\frac{C}{(x-1)^2}+\frac{D}{(x-1)^3}[/tex]
then multiply both sides by[tex](x-1)^3(x+2)[/tex]
then you can solve for D by plugging in x=1 to zero out the other terms
and then plug in x=-2 to solve for A
so A=2 D=1
to solve for B and C expand out those polynomials and then equate the coefficient of the correct powers of x to give you different equations.
so you will equal all the x cubed therms to 0 and the x squared to -4 ... etc.
 
Last edited:
Thank you.
 
your welcome
 

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