Solve Pressurizer Problem: Initial Volume Saturated Vapor

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SUMMARY

The discussion focuses on calculating the initial volume of a pressurizer containing saturated vapor under specific operating conditions. The pressurizer accommodates an outsurge of 30,800 lbm and an insurge of 20,900 lbm, with a necessary water mass of 4,020 lbm to cover electric heaters. The operating pressure is set at 2,250 psia, with hot and cold leg temperatures of 600°F and 550°F, respectively. The key equation involves determining the mass of gas using the relationship between the cold leg spray and hot leg surge, specifically using the value of 0.03.

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ganondorf29
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Homework Statement


A pressurizer is designed to accommodate an outsurge of 30,800 lbm and an insurge of 20900 lbm. The mass of the water necessary to cover the electric heaters is 4020 lbm. The system's operating pressure is 2250 psia. The hot leg is 600F and and the cold leg is 550F (For the hot and cold leg use properties for a compressed liquid). (Cold leg spray / Hot leg surge) = 0.03


Find the initial volume of the pressurizer that is saturated vapor


Homework Equations





The Attempt at a Solution



f = Cold leg spray / Hot leg surge = 0.03

Mass of gas (int) = msurge(1+f)(specific vol of fluid) / (spec vol of fluid - spec vol of gas)

vol of initial gas = mass of initial gas * spec vol of gas


I'm not sure how to find msurge and the 2 specific volumes...
 
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I think that the msurge is the msurge for the insurge, 20900 lbm. We used that equation for Mass of gas (int) for the insurge case in my class anyway.

Additionally the specific volumes are the specific volumes at saturated conditions with a pressure of 2250 psia I think. The inside of a pressurizer contains both liquid and vapor so it should be under saturated conditions. So you could just look up the specific volumes in a steam chart under the listing for 2250 psia for saturated vapor.
 

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